Obtaining the website link using Django's template language

Is there a way in the Django template language to reference the URL? I want to use it on static pages to avoid live links. Can this be accomplished without JavaScript?

I am hoping to achieve something similar to:

{% if current_url == "/about/" %}
About
{% else %}
<a href='/about/'>About</a>
{% endif %}

This is for a basic blog with no specific views created for those pages.

Answer №1

When you mention 'static pages', I believe you are referring to generic views. These views internally make use of RequestContext, providing access to the request object, which represents the current HttpRequest. Therefore, you can obtain the current URL by using request.path.

{% if request.path == '/about/' %}
...
{% endif %}

It is important to note that the if syntax shown above is applicable for Django version 1.2 and newer. For older versions, the following syntax should be used:

{% ifequal request.path '/about/' %}
...
{% endifequal %}

Answer №2

try using request.path instead of current_url in the code snippet you provided above. Make sure you have included

django.core.context_processors.request
for it to work properly. Additionally, remember to use double equals sign == for comparison, not a single equals sign =. Happy coding! :o)

Answer №3

To achieve this, consider implementing simple template inheritance:

# base.html
{% block contactlink %}<a href='/contact/'>Contact</a>{% endblock %}
{% block aboutlink %}<a href='/about/'>About</a>{% endblock %}
  ...

# about.html
{% block aboutlink %}About{% endblock %}

# contact.html
{% block contactlink %}Contact{% endblock %}

It is important to note that this method works effectively when each page has its own separate template. Assuming your pages are static, it should align well with your requirements. Understanding the views you are utilizing (such as generic view direct_to_template) and your urls.py configuration would provide further clarity.

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