obtaining the complete roster of players and storing them in an array

I am dealing with a JSON object that looks like this:

var server = [{
  name: 'xVg1',
  players: ['foo', 'bar','player1'],
  status: "on",
  origin:"",
}, {
  name: 'xVg2',
  players: ['foo1', 'bar1','player2'],
  status: "off",
  origin:"",
}, {
  name: 'xVg3',
  players: ['foo2', 'bar2','player3'],
  status: "on",
  origin:""
}];

My goal is to efficiently extract all the player names into a single array from this object. I want the result to look like this:

player=['foo', 'bar','player1','foo1', 'bar1','player2','foo2', 'bar2','player3']

I attempted to achieve this using a forEach loop, but it resulted in an array of arrays rather than a single array like the desired output shown above.

var arr=[]
server.forEach(val =>{
   arr.push(val.players)
})

Answer №1

Utilize the Array.concat method

Replace

arr.push(val.players)

with

arr = arr.concat(val.players)

var server = [{
  name: 'xVg1',
  players: ['foo', 'bar','player1'],
  status: "on",
  origin:"",
}, {
  name: 'xVg2',
  players: ['foo1', 'bar1','player2'],
  status: "off",
  origin:"",
}, {
  name: 'xVg3',
  players: ['foo2', 'bar2','player3'],
  status: "on",
  origin:""
}];

var arr=[]
server.forEach(val =>{
   arr = arr.concat(val.players)
})

console.log(arr);

Answer №2

By utilizing the reduce function and the spread operator, you can condense your solution into a single line of code

 var server = [{
      name: 'xVg1',
      players: ['foo', 'bar','player1'],
      status: "on",
      origin:"",
    }, {
      name: 'xVg2',
      players: ['foo1', 'bar1','player2'],
      status: "off",
      origin:"",
    }, {
      name: 'xVg3',
      players: ['foo2', 'bar2','player3'],
      status: "on",
      origin:""
    }];
    
    var players = server.reduce((x,y)=>[...x,...y.players],[]);
    console.log(players)

Answer №3

Utilizing the spread operator

var server = [{
  name: 'xVg1',
  players: ['foo', 'bar','player1'],
  status: "on",
  origin:"",
}, {
  name: 'xVg2',
  players: ['foo1', 'bar1','player2'],
  status: "off",
  origin:"",
}, {
  name: 'xVg3',
  players: ['foo2', 'bar2','player3'],
  status: "on",
  origin:""
}];

var res = server.reduce((acc, c) => {
  acc.push(...c.players);
  return acc;
}, []);

console.log(res);

Using the concat method

var server = [{
  name: 'xVg1',
  players: ['foo', 'bar','player1'],
  status: "on",
  origin:"",
}, {
  name: 'xVg2',
  players: ['foo1', 'bar1','player2'],
  status: "off",
  origin:"",
}, {
  name: 'xVg3',
  players: ['foo2', 'bar2','player3'],
  status: "on",
  origin:""
}];
var res = [];
server.forEach((obj) => {
  res = res.concat(obj.players);
});

console.log(res);

Answer №4

Here's a different approach to handling the situation. Just for kicks :)

var server = [{
  name: 'xVg1',
  players: ['foo', 'bar','player1'],
  status: "on",
  origin:"",
}, {
  name: 'xVg2',
  players: ['foo1', 'bar1','player2'],
  status: "off",
  origin:"",
}, {
  name: 'xVg3',
  players: ['foo2', 'bar2','player3'],
  status: "on",
  origin:""
}];


var players = server.map(e=>e.players)
players = [].concat.apply([], players)
console.log(players)

Answer №5

To concatenate arrays using JavaScript, you have a couple of options. One way is to use the reduce() method in combination with .concat():

let result = server.reduce((a, c) => a.concat(c.players), []);

Alternatively, you can achieve the same result with Spread Syntax:

let result = server.reduce((a, c) => (a.push(...c.players), a), []);

Check out this example:

let server = [{name: 'xVg1', players: ['foo', 'bar','player1'], status: "on", origin:""}, {name: 'xVg2', players: ['foo1', 'bar1','player2'], status: "off", origin:""}, {name: 'xVg3', players: ['foo2', 'bar2','player3'], status: "on", origin:""}];

let result = server.reduce((a, c) => a.concat(c.players), []);

console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Explore more:

Answer №6

If you are utilizing the forEach() method, then within the forEach() loop, you have the option to use Spread_syntax.

EXAMPLE


const server = [{
  name: 'xVg1',
  players: ['foo', 'bar','player1'],
  status: "on",
  origin:"",
}, {
  name: 'xVg2',
  players: ['foo1', 'bar1','player2'],
  status: "off",
  origin:"",
}, {
  name: 'xVg3',
  players: ['foo2', 'bar2','player3'],
  status: "on",
  origin:""
}];

let result = [];
server.forEach(obj => {
    result.push(...obj.players);
});

console.log(result);
   
.as-console-wrapper { max-height: 100% !important; top: 0; }

You can make use of reduce() along with Spread syntax to accomplish the desired outcome.

EXAMPLE

const server = [{
  name: 'xVg1',
  players: ['foo', 'bar', 'player1'],
  status: "on",
  origin: "",
}, {
  name: 'xVg2',
  players: ['foo1', 'bar1', 'player2'],
  status: "off",
  origin: "",
}, {
  name: 'xVg3',
  players: ['foo2', 'bar2', 'player3'],
  status: "on",
  origin: ""
}]

let result = server.reduce((arr, object) => [...arr, ...object.players], []);

console.log(result)
.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer №7

Utilize the Underscore.js library, which offers a wide array of helpful functional programming tools without expanding any built-in objects.

var data = [{
      name: 'xVg1',
      players: ['foo', 'bar','player1'],
      status: "on",
      origin:"",
    }, {
      name: 'xVg2',
      players: ['foo1', 'bar1','player2'],
      status: "off",
      origin:"",
    }, {
      name: 'xVg3',
      players: ['foo2', 'bar2','player3'],
      status: "on",
      origin:""
    }];

    var output = _.flatten(_.pluck(data,"players"));
    
    console.log(output);

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