I'm trying to find a way to get the top 3 keys from a dictionary like this:
dict = {"apple": 1, "orange":10,"watermelon":5, "banana":15}
. Any ideas on how I can achieve this?
// Expected output: ["banana","orange", "watermelon"]
I'm trying to find a way to get the top 3 keys from a dictionary like this:
dict = {"apple": 1, "orange":10,"watermelon":5, "banana":15}
. Any ideas on how I can achieve this?
// Expected output: ["banana","orange", "watermelon"]
Utilize the Object.entries
method along with destructuring to efficiently arrange in order, extract top 3 elements from the sorted entries array, then use map
to generate an array consisting of fruit names:
const dict = {"apple": 1, "orange":10,"watermelon":5, "banana":15};
const top3 = Object
.entries(dict) // convert into Array of Arrays [key, value]
.sort(([, a],[, b]) => b-a) // sort by value in descending order
.slice(0,3) // select only the first 3 elements from the sorted list
.map(([n])=> n); // map it to an array containing only the name
console.log(top3);
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