Obtain a series of numbers from the arranged array

Question

Obtain a series of numbers from the arranged array

Consider a sorted array containing numbers, for instance:

const array = [100, 400, 700, 1000, 1300, 1600]

We have a function that requires two arguments as input:

function foobar(min, max) {}

The task of this function is to retrieve the numbers from the array, starting from the first value that is >= to the min and ending with the last value that is >= to the max.

foobar(250, 1010) // returns [400, 700, 1000, 1300]
foobar(0, 15) // returns [100]

How can we achieve this using modern JavaScript?

array.filter((num) => {
  return num >= min && num <= max
})

This solution always excludes the last number. 🤔

javascript math

Answer 1

Answer №1

This code snippet showcases the efficiency of using a for...of loop.

const numbers = [100, 400, 700, 1000, 1300, 1600];

function filterNumbers(arr, min, max) {
    let result = [];
    for (let num of arr) {
        if(min <= num && num <= max) {
            result.push(num);
        } else if(num > max) {
            result.push(num);
            break;
        }
    }
    return result;
}

console.log(filterNumbers(numbers, 0, 15));     // outputs [100]
console.log(filterNumbers(numbers, 250, 1010)); // outputs [400, 700, 1000, 1300]

This approach is straightforward, adheres to traditional programming principles, and iterates through the array efficiently in a single pass.

Answer 2

This code snippet showcases the efficiency of using a for...of loop.

const numbers = [100, 400, 700, 1000, 1300, 1600];

function filterNumbers(arr, min, max) {
    let result = [];
    for (let num of arr) {
        if(min <= num && num <= max) {
            result.push(num);
        } else if(num > max) {
            result.push(num);
            break;
        }
    }
    return result;
}

console.log(filterNumbers(numbers, 0, 15));     // outputs [100]
console.log(filterNumbers(numbers, 250, 1010)); // outputs [400, 700, 1000, 1300]

This approach is straightforward, adheres to traditional programming principles, and iterates through the array efficiently in a single pass.

Answer 3

Answer №2

Let's explore a solution

const numbers = [100, 400, 700, 1000, 1300, 1600];

const filterNumbers = (minValue, maxValue) => {

    const lowestHigherNumber = numbers.find(num => (num >= maxValue));
    
    const isWithinRange = value => (value >= minValue && value <= lowestHigherNumber);
    return numbers.filter(isWithinRange);
};

console.log( filterNumbers(0, 150) );
console.log( filterNumbers(400, 1500) );

Answer 4

Let's explore a solution

const numbers = [100, 400, 700, 1000, 1300, 1600];

const filterNumbers = (minValue, maxValue) => {

    const lowestHigherNumber = numbers.find(num => (num >= maxValue));
    
    const isWithinRange = value => (value >= minValue && value <= lowestHigherNumber);
    return numbers.filter(isWithinRange);
};

console.log( filterNumbers(0, 150) );
console.log( filterNumbers(400, 1500) );

Obtain a series of numbers from the arranged array

Answer №1

Answer №2

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