Not all elements of an array are returned by an arrow function with conditionals

My array looks like this:

var arr = ['one', 'two', ['three', 'four']];

When attempting to use arrow functions to return each element, the third element shows up as undefined instead of the actual values. I've tried restructuring it without success. While I could resort to using a for loop and push method, I prefer to grasp how to properly utilize arrow functions in situations like this.

arr.map(e => {
 if(typeof(e) == "object"){
    e.map(t => t)
  } else{ return e; }
})

Any insights on this issue would be greatly appreciated. The desired output should be an array like so: ['one', 'two', 'three', 'four'].

Answer №1

Array.prototype.map() does not have the functionality to flatten an array. Even if .map() could flatten an array, the code snippet e.map(t => t) does not actually return anything from the callback function within .map().

arr.map(e => {
 if(typeof(e) == "object"){
    e.map(t => t) // no value is `return`ed here
  } else{ return e; }
})

There are multiple approaches and methods in JavaScript's Array that can be utilized to flatten an Array, such as .flat(), .flatMap(), and .concat(). For more details, you can refer to Merge/flatten an array of arrays in JavaScript?

Answer №2

In order to get the desired outcome, you can utilize the following method of using reduce to extract all elements from an array encapsulated within another array.

var arr = ['one', 'two', ['three', 'four']];

console.log(arr.reduce((acc, v) => {
  typeof(v) == 'object' ? acc.push(...v) : acc.push(v)
  return acc
}, []))



           

Check out the codepen here - https://codepen.io/nagasai/pen/NJKdKv

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