I'm looking for assistance on how to round up to the nearest 0.10 with a minimum of 2.80.
var panel;
if (routeNodes.length > 0 && (panel = document.getElementById('distance')))
{
panel.innerHTML = (dist/1609.344).toFixed(2) + " miles = £" + (((dist/1609.344 - 1) * 1.20) + 2.80).toFixed(2);
}
If anyone could offer guidance, it would be greatly appreciated.
let amount = 123.123;
Math.max( Math.round(amount * 10) / 10, 2.8 ).toFixed(2);
When you want to get the rounded-up value, you can utilize Math.ceil:
Math.max( Math.ceil(number2 * 10) / 10, 2.8 )
First, multiply the number by 10, round it off, and then divide by 10 again for precision.
(Math.round(15.276 * 10) / 10).toFixed(2)
Alternatively:
Number(15.276.toFixed(1)).toFixed(2)
In your script:
var box;
if (blocks.length > 0 && (box = document.getElementById('size')))
{
box.innerHTML = Number((size/2000.456).toFixed(1)).toFixed(2)
+ " units = £"
+ Number((((size/2000.456 - 1) * 1.50) + 3.00).toFixed(1)).toFixed(2);
}
To set a minimum value, utilize the Math.max method:
var x = 12.7, y = 3.4, z = 8.9;
alert(Math.max(x, 6.5)); // will show 12.7 (x);
alert(Math.max(y, 6.5)); // will show 6.5 since it is bigger than y (3.4);
alert(Math.max(z, 6.5)); // will display 8.9 (z);
Discover a popular method for rounding numbers in JavaScript that is commonly found on top search results. While this solution addresses a more general question, it can still be useful for specific cases. By using the following inline function:
const round = (num, grainularity) => Math.round(num / grainularity) * grainularity;Feel free to test it out with the examples provided below:
const round = (num, grainularity) => Math.round(num / grainularity) * grainularity;
const test = (num, grain) => {
console.log(`Rounding to the nearest ${grain} for ${num} -> ${round(num, grain)}`);
}
test(1.5, 1);
test(1.5, 0.1);
test(1.5, 0.5);
test(1.7, 0.5);
test(1.9, 0.5);
test(-1.9, 0.5);
test(-1.2345, 0.214);let distance_miles = distance/1609.344;
distance_miles = Math.round(distance_miles*10)/10;
distance_miles = distance_miles < 2.80 ? 2.80 : distance_miles;
If you need to round to the nearest 0.10, one method is to multiply the number by 10, use the Math.round function to round it, and then divide by 10.
Find the closest tenth:
Get the highest number between x and 2.8, then fix it to one decimal place and add '0'
Round up to the nearest hundredth:
Get the ceiling value of x multiplied by 10 divided by 10, compare it to 2.8, then fix it to two decimal places
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