Navigating through and extracting data from an object in JavaScript

Given the function call

destroyer([1, 2, 3, 1, 2, 3], 2, 3);
, I am trying to retrieve the last 2, 3 part after the initial array. However, I am unsure about how to achieve this.

When I use return arr[6]; or return arr[1][0], both statements do not return the expected output of 2 or 2, 3 (last two numbers).

I attempted to find a solution by researching Property Accessors, but it seems like I was looking in the wrong place for the answer.

Below is my current code:

function destroyer(arr) {
  return arr;
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Instead of obtaining the complete array [1, 2, 3, 1, 2, 3], my goal is to extract the elements following the array:

[1, 2, 3, 1, 2, 3], 2, 3

Answer №1

Looks like your destroyer function is designed to take only one argument, but you've passed it 3.

You have a couple of options:

  1. Utilize arguments to access an array-like structure containing all the passed arguments. You can then use methods like slice to extract the desired second and third arguments. Keep in mind that since arguments is not technically an array, you may need to convert it before using methods like slice. In the provided example, I used Array.from, which may not be supported on older browsers.

function destroyer(arr) {
  return Array.from(arguments).slice(1, 3);
}

console.log('Result: ', destroyer([1, 2, 3, 1, 2, 3], 2, 3));

  1. Add extra parameters to your function declaration. This approach could be simpler if you are certain that you will always receive exactly 3 arguments. It involves fewer complexities compared to working with the arguments variable.

function destroyer(a, b, c) {
  return [b, c];
}

console.log('Result: ', destroyer([1, 2, 3, 1, 2, 3], 2, 3));

Answer №2

attempt to utilize arguments illustration

function destructor(){var array = []; array.push(arguments[1]);array.push(arguments[2]); return array};

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