Modify the JavaScript regular expression to be compatible with Java programming language

Question

Modify the JavaScript regular expression to be compatible with Java programming language

I stumbled upon this JavaScript regex that extracts IDs from the Youtube URLs provided below:

/(youtu(?:\.be|be\.com)\/(?:.*v(?:\/|=)|(?:.*\/)?)([\w'-]+))/i

Youtube URLs tested on:

http://www.youtube.com/user/Scobleizer#p/u/1/1p3vcRhsYGo

http://www.youtube.com/watch?v=cKZDdG9FTKY&feature=channel

... (other YouTube URLs listed)

How can I adapt this regex for use in Java? And is it possible to modify it to extract IDs from gdata URLs as well? For example,

https://gdata.youtube.com/feeds/api/users/Test/?alt=json&v=2

Update: This is where I intend to implement the Regex function.

public static String getIDFromYoutubeURL(String ytURL ) {
    if(ytURL.startsWith("https://gdata")) {  // This is my temporary workaround,      
       ytURL = ytURL.replace("v=\\d", ""); // I believe the Regex should handle this.
    }
    String pattern = "(?i)(https://gdata\\.)?(youtu(?:\\.be|be\\.com)/(?:.*v(?:/|=)|(?:.*/)?)([\\w'-]+))";
    Pattern compiledPattern = Pattern.compile(pattern);
    Matcher matcher = compiledPattern.matcher(ytURL);

    if(matcher.find()){
        return matcher.group(3);
    }
    return null;
}

The current implementation works for most YouTube URLs and also for

https://gdata.youtube.com/feeds/api/users/Test/?id=c

. However, it fails when dealing with Gdata URLs that contain version parameters, like v=2 (

https://gdata.youtube.com/feeds/api/users/Test/?id=c&v=2

). In such cases, it returns 2 instead of Test as the ID. How can I enhance it to retrieve Test instead of 2 as the ID in Gdata URLs? Thanks.

java javascript regex youtube gdata

Answer 1

Answer №1

Fixed the issue!
Switch to using replaceAll method:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class YouTubeExtractor {
    public YouTubeExtractor() {
        // Constructor
    }

    public static void main(String[] args) {
        String extractedID = extractIDFromYouTubeURL(
                "https://gdata.youtube.com/feeds/api/users/Test/?id=c&v=2");
        System.out.println(extractedID);
    }

    public static String extractIDFromYouTubeURL(String ytURL ) {
        if(ytURL.startsWith("https://gdata")) {  
           ytURL = ytURL.replaceAll("v=\\d", "");
        }
        String pattern = "(?i)(https://gdata\\.)?(youtu(?:\\.be|be\\.com)/(?:.*v(?:/|=)|(?:.*/)?)([\\w'-]+))";
        Pattern compiledPattern = Pattern.compile(pattern);
        Matcher matcher = compiledPattern.matcher(ytURL);

        if(matcher.find()){
            return matcher.group(3);
        }
        return null;
    }
}

Answer 2

Fixed the issue!
Switch to using replaceAll method:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class YouTubeExtractor {
    public YouTubeExtractor() {
        // Constructor
    }

    public static void main(String[] args) {
        String extractedID = extractIDFromYouTubeURL(
                "https://gdata.youtube.com/feeds/api/users/Test/?id=c&v=2");
        System.out.println(extractedID);
    }

    public static String extractIDFromYouTubeURL(String ytURL ) {
        if(ytURL.startsWith("https://gdata")) {  
           ytURL = ytURL.replaceAll("v=\\d", "");
        }
        String pattern = "(?i)(https://gdata\\.)?(youtu(?:\\.be|be\\.com)/(?:.*v(?:/|=)|(?:.*/)?)([\\w'-]+))";
        Pattern compiledPattern = Pattern.compile(pattern);
        Matcher matcher = compiledPattern.matcher(ytURL);

        if(matcher.find()){
            return matcher.group(3);
        }
        return null;
    }
}

Answer 3

Answer №2

Utilize the Pattern flag for case insensitivity when needed. Here's an example:

Pattern pattern = Pattern.compile("(youtu(?:\\.be|be\.com)\\/(?:.*v(?:\\/|=)|(?:.*\\/)?)([\\w'-]+))", Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(text_to_scan);
String result = matcher.group();

Answer 4

Utilize the Pattern flag for case insensitivity when needed. Here's an example:

Pattern pattern = Pattern.compile("(youtu(?:\\.be|be\.com)\\/(?:.*v(?:\\/|=)|(?:.*\\/)?)([\\w'-]+))", Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(text_to_scan);
String result = matcher.group();

Modify the JavaScript regular expression to be compatible with Java programming language

Answer №1

Answer №2

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