I need help changing the form action based on which button is clicked.
Form
<form action="addline.php" method="post" id="rundataform">
.....
<input value="Select1" type="submit" class="button1" > // click this to run addline.php
<input value="Select2" type="submit" class="button2" > // click this to run addline2.php
</form>
I have tried using JavaScript but couldn't get it to work. Can someone provide me with a working code snippet?
Kris
<form action="addline.php" method="post" id="rundataform">
<script>
function switchAction(value) {
document.forms[0].action = value;
}
</script>
<input value="Select1" onmouseover="switchAction('addline.php')" type="submit" class="button1" > // button one
<input value="Select2" onmouseover="switchAction('addline1.php')" type="submit" class="button2" > // button two
</form>Here's a simple trick to achieve this:
<form action="addline.php" method="post" id="rundataform">
<script>
function switchAction(value) {
document.forms[0].action = value;
}
</script>
<input value="Select1" onmouseover="switchAction('addline.php')" type="submit" class="button1" > // button one
<input value="Select2" onmouseover="switchAction('addline1.php')" type="submit" class="button2" > // button two
</form>
If you're looking to utilize ajax functionality, here's a helpful tip.
<script type="text/javascript><
$(#button).click(function(){
$.ajax({
type: 'POST',
url: 'required.php',
success: function(data) {
}
});
});
</script>
This method allows you to specify the button id and designate the desired URL of the php file for control transfer.
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