Looking to find digits but not when they are part of words (using JavaScript).
The examples that should yield a match:
1
1,2
1.5-4 (matches 1.5 & 4 separately)
(1+3) (matches 1 & 3 separately)
=1;
The following examples should NOT produce a match:
FF3D
3deg
I attempted to use negative lookahead with this pattern:
(?![A-Za-z]+)([0-9]+[\.|\,]?[0-9]?)What is the best approach to addressing this issue? Thank you.
I need help finding numbers in a string, but only if they are not part of a word.
You can achieve this using look arounds in your regular expression:
\b\d*[,.]?\d+\b
\b represents a word boundaryUpdate for 2021:
Due to the significant growth in lookbehind support, it is recommended to use a lookbehind-based solution like this:
/(?<!\w)\d*[.,]?\d+(?!\w)/gi # ASCII only
/(?<!\p{L})\p{N}*[.,]?\p{N}+(?!\p{L})/giu # Unicode-aware
You can see the regex demo here. Keep track of lookbehind and Unicode property class support on this page.
More Information
(?<![a-z]) - there should not be any ASCII letter (or any Unicode letter if using \p{L}) immediately to the left\d*[.,]?\d+(?![a-z]) - there should not be any ASCII letter (or any Unicode letter if using \p{L}) immediately to the right.Original Answer
If you want to match standalone integer or float numbers with dot or comma as decimal separators, you can use the following pattern:
/(?:\b\d+[,.]|\B[.,])?\d+\b/g
Check out the regex demo here. The key point is that you cannot use a word boundary \b before a . because it will exclude matches like .55 (only 55 will be matched).
Details:
(?:\b\d+[,.]|\B[.,])? - either of these alternatives:
\b\d+[,.] - a word boundary (must include a non-word character before or start of string), then 1+ digits, followed by a . or ,| - or\B[.,] - a position that is not a word boundary (only includes a non-word character or start of string) followed by a . or ,\d+ - 1+ digits\b - a word boundary.const regex = /(?:\b\d+[,.]|\B[.,])?\d+\b/g;
const str = `.455 and ,445 44,5345 435.54 4444
1
1,2
1.5-4
(1+3)
=1;
FF3D
3deg`;
console.log(str.match(regex));If you also need to add support for exponents, you can use this pattern:
/(?:\b\d+[,.]|\B[.,])?\d+(?:e[-+]?\d+)?\b/ig
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