Looping through numbers from 0 to 100, calculating and displaying the total sum of even numbers and odd numbers separately in an array

Question

Looping through numbers from 0 to 100, calculating and displaying the total sum of even numbers and odd numbers separately in an array

I am attempting to iterate through numbers from 0 to 100 and calculate the sum of even numbers and odd numbers in an array format, for example [2550, 2500].

let total = 0;

for(let num = 0; num <= 100; num++) { 
  total = total + num;
}

console.log(Array.from(String(total)));

However, this code outputs ['2', '5', '0', '0']

Could someone please guide me on how to display both sums as arrays?

Additionally, I need help with incorporating this code into another conditional statement so that I can obtain both the sum of odd numbers and even numbers. I'm having trouble deciding whether to use else if or if else....

javascript arrays math

Answer 1

Answer №1

To determine if a number is even or odd, simply check the remainder when divided by 2. If the remainder is zero, it's even; otherwise, it's odd.

let totalEven = 0;
let totalOdd = 0;

for(let num = 0; num <= 100; num++) {
    if(num % 2 === 0) {
        totalEven += num;
    } else {
        totalOdd += num;
    }
}

Finally, you can output the totals for both even and odd numbers using

console.log([totalEven, totalOdd])

.

Answer 2

To determine if a number is even or odd, simply check the remainder when divided by 2. If the remainder is zero, it's even; otherwise, it's odd.

let totalEven = 0;
let totalOdd = 0;

for(let num = 0; num <= 100; num++) {
    if(num % 2 === 0) {
        totalEven += num;
    } else {
        totalOdd += num;
    }
}

Finally, you can output the totals for both even and odd numbers using

console.log([totalEven, totalOdd])

.

Answer 3

Answer №2

Since you've tagged this question with mathematics, I believe it's worth mentioning the concept of triangular numbers:

function calculateOddEvenSum(value) {
    const floorVal = Math.floor(value / 2);
    const ceilVal = Math.ceil(value / 2);
    return [ceilVal * ceilVal, floorVal * (1 + floorVal)];
}

console.log(calculateOddEvenSum(100))

Without using a function:

const value = 100; // Example
const floorVal = Math.floor(value / 2);
const ceilVal = Math.ceil(value / 2);
const resultArray = [ceilVal * ceilVal, floorVal * (1 + floorVal)];
console.log(resultArray)

Answer 4

Since you've tagged this question with mathematics, I believe it's worth mentioning the concept of triangular numbers:

function calculateOddEvenSum(value) {
    const floorVal = Math.floor(value / 2);
    const ceilVal = Math.ceil(value / 2);
    return [ceilVal * ceilVal, floorVal * (1 + floorVal)];
}

console.log(calculateOddEvenSum(100))

Without using a function:

const value = 100; // Example
const floorVal = Math.floor(value / 2);
const ceilVal = Math.ceil(value / 2);
const resultArray = [ceilVal * ceilVal, floorVal * (1 + floorVal)];
console.log(resultArray)

Answer 5

Answer №3

This code snippet calculates the total sum of numbers within the range of 0 to 100.

The variable m holds the sum of the range(0-100), which is 5050.

for(let i=0;i<=100;i++) { 
  m = m + i;
}

The following line splits the digits of the variable m and creates an array from them.

console.log(Array.from(String(m)));

['5','0','5','0']

You can create two variables for even_sum and odd_sum, then check if a number is odd or even, adding it to the appropriate sum.

let even_sum=0;
let odd_sum=0;

for(let i=0;i<=100;i++) { 
    if (i%2==0)
        even_sum+=i;
    else
        odd_sum+=i;
}

To return the values as an array, you can use the following code:

console.log([even_sum,odd_sum])

Answer 6

This code snippet calculates the total sum of numbers within the range of 0 to 100.

The variable m holds the sum of the range(0-100), which is 5050.

for(let i=0;i<=100;i++) { 
  m = m + i;
}

The following line splits the digits of the variable m and creates an array from them.

console.log(Array.from(String(m)));

['5','0','5','0']

You can create two variables for even_sum and odd_sum, then check if a number is odd or even, adding it to the appropriate sum.

let even_sum=0;
let odd_sum=0;

for(let i=0;i<=100;i++) { 
    if (i%2==0)
        even_sum+=i;
    else
        odd_sum+=i;
}

To return the values as an array, you can use the following code:

console.log([even_sum,odd_sum])

Answer 7

Answer №4

Utilize an array to calculate the sum of each parity separately.

arr=[0,0];
for (i=0;i<101;i++)
arr[i%2]+=i;
console.log(arr);

Answer 8

Utilize an array to calculate the sum of each parity separately.

arr=[0,0];
for (i=0;i<101;i++)
arr[i%2]+=i;
console.log(arr);

Looping through numbers from 0 to 100, calculating and displaying the total sum of even numbers and odd numbers separately in an array

Answer №1

Answer №2

Answer №3

Answer №4

Similar questions

Exploring Nashorn's Global Object Variables Through Access and Intercept Techniques

Is it possible to access the grid in ASP.NET Kendoui through code?

Develop a Greasemonkey userscript that eliminates specific HTML lines upon detection

Trouble arises when the properties of this.props are supposed to exist, yet they are not

Not all elements are removed by an array

Updating a route in Next.js? Make sure to remove the classList as you

Having trouble activating the Invalidate Cache function in rtk query with tags

Is it necessary to validate my form multiple times?

Consolidate all important values into a single NSMutable Array

Issue with generating WebGL shaders

What is the process of displaying multiple static files using Express?

Transferring a JavaScript object to a Vue.js component

Tips for implementing fluid transitions between mouse X and Y coordinates using JavaScript

Refreshing a div component in Rails by using JavaScript after form submission

How can I determine if my clients are utilizing the CDN or NPM versions of my JavaScript library?

How to replicate the functionality of jQuery's each() method to get the height

"Unleashing the Power of Effortless Object Unwr

Getting Started with the Basic Example of Redux-Router

Looking for a specific value within an array in PHP

What is the best method to eliminate elements from one array based on the presence of an element in another array in Python