Loop through each object in an array and verify if the value matches a specific criteria in Javascript

Question

Loop through each object in an array and verify if the value matches a specific criteria in Javascript

Explore the common issues related to object iteration and queries outlined below.

Presented here is a list of objects (used for managing a connection form):

const connectionData = {
  mail: {
    value: false,
    isRequired: true
  },
  password: {
    value: false,
    isRequired: true
  },
  name: {
    value: false,
    isRequired: false
  },
}

Included below is an array variable that contains all the objects from connectionData

const fieldsToCheck = [connectionData.mail, connectionData.password, connectionData.name]

The intention of the check function below is to verify if:

For each object in fieldsToCheck where isRequired is true, if value is false, return true, otherwise, return false

const check = () => {
  if((fieldsToCheck.filter(key => 
    key.isRequired).every(val => 
        !val.value))) {
            return true
  } else {
    return false
  }
}

This function adequately serves its purpose. With the current object values, it returns true, and false if values are altered to true or ""

I pondered if there might be a quicker or more refined method of achieving the same outcome.

Wishing everyone a pleasant day ahead!

javascript arrays object methods iteration

Answer 1

Answer №1

To achieve the desired outcome, consider switching from using .filter() to .every() directly on the fieldstocheck array. By doing so, you eliminate the creation of a new array in memory and reduce the number of iterations, as the array is only iterated through once:

const connexionData = { mail: { value: false, isRequired: true }, password: { value: false, isRequired: true }, name: { value: false, isRequired: false }, }

const fieldstocheck = [connexionData.mail, connexionData.password, connexionData.name];

const res = fieldstocheck.every((obj) => !obj.isRequired || !obj.value);
console.log(res);

Within the code snippet, the logic checks if isRequired is false with !obj.isRequired. If true, the .every() callback method returns true for that object. If isRequired is true, it then examines obj.value to determine its falseness: !obj.value.

From a propositional logic perspective, the condition:

!obj.isRequired || !obj.value

is equivalent to

!(obj.isRequired && obj.value)

(refer to De Morgan's law for further clarification). This alternative interpretation considers whether the object is required and contains a value, returning false, or otherwise, true (if it's not required or lacks a value).

Answer 2

To achieve the desired outcome, consider switching from using .filter() to .every() directly on the fieldstocheck array. By doing so, you eliminate the creation of a new array in memory and reduce the number of iterations, as the array is only iterated through once:

const connexionData = { mail: { value: false, isRequired: true }, password: { value: false, isRequired: true }, name: { value: false, isRequired: false }, }

const fieldstocheck = [connexionData.mail, connexionData.password, connexionData.name];

const res = fieldstocheck.every((obj) => !obj.isRequired || !obj.value);
console.log(res);

Within the code snippet, the logic checks if isRequired is false with !obj.isRequired. If true, the .every() callback method returns true for that object. If isRequired is true, it then examines obj.value to determine its falseness: !obj.value.

From a propositional logic perspective, the condition:

!obj.isRequired || !obj.value

is equivalent to

!(obj.isRequired && obj.value)

(refer to De Morgan's law for further clarification). This alternative interpretation considers whether the object is required and contains a value, returning false, or otherwise, true (if it's not required or lacks a value).

Loop through each object in an array and verify if the value matches a specific criteria in Javascript

Answer №1

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