Looking to develop a method that extracts a value from an array, saves it, and transfers it to another array exclusively through the use of .pop and .push methods

Question

Looking to develop a method that extracts a value from an array, saves it, and transfers it to another array exclusively through the use of .pop and .push methods

I'm currently working on an assignment for my JS course that involves creating a function using only .push and .pop commands. The task is to take the last value from the first array and move it to the second array. Unfortunately, I seem to be messing something up in my code.

Here's the example we were given to follow:

let anArray = [1, 2];
let anotherArray = [3, 4];

move(anArray, anotherArray);

anArray //should be [1]
anotherArray //should be [3,4,2]

And here's what I've attempted so far:

function move(parameter1, parameter2){
    var anArray = [1, 2];
    var anotherArray = [3, 4];
    var storage = anArray.pop();
    anotherArray.push(storage);
}

I'm seeking some guidance as to why my function doesn't seem to be working as expected. I'm fairly new to JavaScript, so any help would be greatly appreciated.

Thank you,

Luis.

javascript arrays function

Answer 1

Answer №1

Your function parameters were unused, instead, you created new variables. Here's a corrected example:

function swap(arr1, arr2) {
  var temp = arr1.pop();
  arr2.push(temp);
}
let myArray = [1, 2];
let yourArray = [3, 4];

swap(myArray, yourArray)
console.log(myArray)
console.log(yourArray)

Answer 2

Your function parameters were unused, instead, you created new variables. Here's a corrected example:

function swap(arr1, arr2) {
  var temp = arr1.pop();
  arr2.push(temp);
}
let myArray = [1, 2];
let yourArray = [3, 4];

swap(myArray, yourArray)
console.log(myArray)
console.log(yourArray)

Answer 3

Answer №2

One reason for the confusion is that in the function move, you redefined anArray and anotherArray. The scope of the outer arrays is different from the variables defined inside the function. The actual movement of elements is happening within the arrays defined inside the method. The confusion arises from using the same names for both sets of arrays.

Below is the implementation you have created, which is functional but not based on the parameters passed:

function move(parameter, parameter2) {
  var anArray = [1, 2];
  var anotherArray = [3, 4];
  var storage = anArray.pop();
  anotherArray.push(storage);
  console.log(anArray)
  console.log(anotherArray)
}

move([],[])

In order to make your function work with the input parameters passed, you can make the following changes:

function move(parameter, parameter2) {
  const storage = parameter.pop();
  parameter2.push(storage);
}

let anArray = [1, 2];
let anotherArray = [3, 4];

move(anArray, anotherArray)
console.log(anArray)
console.log(anotherArray)

I hope this explanation is helpful to you.

Answer 4

One reason for the confusion is that in the function move, you redefined anArray and anotherArray. The scope of the outer arrays is different from the variables defined inside the function. The actual movement of elements is happening within the arrays defined inside the method. The confusion arises from using the same names for both sets of arrays.

Below is the implementation you have created, which is functional but not based on the parameters passed:

function move(parameter, parameter2) {
  var anArray = [1, 2];
  var anotherArray = [3, 4];
  var storage = anArray.pop();
  anotherArray.push(storage);
  console.log(anArray)
  console.log(anotherArray)
}

move([],[])

In order to make your function work with the input parameters passed, you can make the following changes:

function move(parameter, parameter2) {
  const storage = parameter.pop();
  parameter2.push(storage);
}

let anArray = [1, 2];
let anotherArray = [3, 4];

move(anArray, anotherArray)
console.log(anArray)
console.log(anotherArray)

I hope this explanation is helpful to you.

Looking to develop a method that extracts a value from an array, saves it, and transfers it to another array exclusively through the use of .pop and .push methods

Answer №1

Answer №2

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