Looking for assistance to find the largest sequence of 3 consecutive numbers within a string in javascript?

Question

Looking for assistance to find the largest sequence of 3 consecutive numbers within a string in javascript?

In my function, I am tasked with receiving a string of numbers as input. My objective is to identify the largest consecutive three-digit number within the string and then return it.

function findLargestThreeDigitNum(numString){

    let largestNumber = 0;
    let largestThreeNumber = 0; 

    for(let i= 0; i<numString.length; ++i){
        if(numString[i] === largestNumber){
            largestThreeNumber = largestNumber++
        }
    }
    return largestThreeNumber; 
}

javascript string numbers

Answer 1

Answer №1

Check out this handy script that can help you find the 3 largest consecutive numbers

function findLargestThreeNums(numString) {
  var nums = [];
  
  // Go through the string to identify all sets of 3 consecutive numbers
  for (var i = 0; i < numString.length - 2; i++) { 
    nums.push(numString.slice(i, i + 3));
  }

  nums.sort() // Sort the list from smallest to largest
  return nums[nums.length - 1] // Return the largest number from the list
}

console.log(findLargestThreeNums("693759936") )

Answer 2

Check out this handy script that can help you find the 3 largest consecutive numbers

function findLargestThreeNums(numString) {
  var nums = [];
  
  // Go through the string to identify all sets of 3 consecutive numbers
  for (var i = 0; i < numString.length - 2; i++) { 
    nums.push(numString.slice(i, i + 3));
  }

  nums.sort() // Sort the list from smallest to largest
  return nums[nums.length - 1] // Return the largest number from the list
}

console.log(findLargestThreeNums("693759936") )

Answer 3

Answer №2

Assuming you have an input string like "123 465 789", here is a method to extract the largest three-digit numbers from it. Split the string by spaces, filter out only the 3-digit numbers, sort them, and then take the last three in the sorted list.

getLargestThreeDigits = numString => numString
                                       .split(" ") // split by spaces 
                                       .filter(n => n.length === 3) // keep only 3 digit numbers
                                       .sort()
                                       .slice(-3) // get the last three

console.log( getLargestThreeDigits("56 456 321 78 987 123 741 2 96 41 58 654") )

Answer 4

Assuming you have an input string like "123 465 789", here is a method to extract the largest three-digit numbers from it. Split the string by spaces, filter out only the 3-digit numbers, sort them, and then take the last three in the sorted list.

getLargestThreeDigits = numString => numString
                                       .split(" ") // split by spaces 
                                       .filter(n => n.length === 3) // keep only 3 digit numbers
                                       .sort()
                                       .slice(-3) // get the last three

console.log( getLargestThreeDigits("56 456 321 78 987 123 741 2 96 41 58 654") )

Answer 5

Answer №3

Breaking down the problem into smaller tasks and solving them with concise functions can be an effective approach. Here's a breakdown of how we tackle the problem:

Convert the given string into an array
Divide the array into chunks of three digits, or as close to three as possible
Filter out any chunks that do not contain exactly three numbers
Convert each chunk of 3 'number' strings into a single number
Determine the largest number from the set
Return the largest number found

If speed is your primary concern, this may not be the most efficient solution for you. However, if you prefer a solution composed of small, reusable pieces, then this method could be suitable.

const splitIntoAllChunks = size => array => Object.values(
  array
    .reduce((prev, _, i) => ({
      ...prev,
      [i]: array.slice(i, i + size),
    }), {})
);
  
const splitIntoThrees = splitIntoAllChunks(3);

const isLength = length => array => array.length === length;

const stringArrayToNumber = array => Number(array.join(''));

const getMax = (champ, challenger) => challenger > champ ? challenger : champ;

const example = "184727158129123"

const result = splitIntoThrees(example.split(''))
  .filter(isLength(3))
  .map(stringArrayToNumber)
  .reduce(getMax, 0);
  
console.dir(result);

If you prefer sticking closer to your original solution, you can make some adjustments like so:

const testData = "1234596789"

function largestThreeDigitNum(numString){

    let numberSize = 3;
    let largestThreeNumber = 0; 

    for (let i = 0; i < numString.length - (numberSize - 1); i++){
 
        const thisNumber = Number(numString.slice(i, i + 3))
        
        if(thisNumber > largestThreeNumber){
            largestThreeNumber = thisNumber;
        }
    }
    return largestThreeNumber; 
}

console.dir(largestThreeDigitNum(testData))

Answer 6

Breaking down the problem into smaller tasks and solving them with concise functions can be an effective approach. Here's a breakdown of how we tackle the problem:

Convert the given string into an array
Divide the array into chunks of three digits, or as close to three as possible
Filter out any chunks that do not contain exactly three numbers
Convert each chunk of 3 'number' strings into a single number
Determine the largest number from the set
Return the largest number found

If speed is your primary concern, this may not be the most efficient solution for you. However, if you prefer a solution composed of small, reusable pieces, then this method could be suitable.

const splitIntoAllChunks = size => array => Object.values(
  array
    .reduce((prev, _, i) => ({
      ...prev,
      [i]: array.slice(i, i + size),
    }), {})
);
  
const splitIntoThrees = splitIntoAllChunks(3);

const isLength = length => array => array.length === length;

const stringArrayToNumber = array => Number(array.join(''));

const getMax = (champ, challenger) => challenger > champ ? challenger : champ;

const example = "184727158129123"

const result = splitIntoThrees(example.split(''))
  .filter(isLength(3))
  .map(stringArrayToNumber)
  .reduce(getMax, 0);
  
console.dir(result);

If you prefer sticking closer to your original solution, you can make some adjustments like so:

const testData = "1234596789"

function largestThreeDigitNum(numString){

    let numberSize = 3;
    let largestThreeNumber = 0; 

    for (let i = 0; i < numString.length - (numberSize - 1); i++){
 
        const thisNumber = Number(numString.slice(i, i + 3))
        
        if(thisNumber > largestThreeNumber){
            largestThreeNumber = thisNumber;
        }
    }
    return largestThreeNumber; 
}

console.dir(largestThreeDigitNum(testData))

Answer 7

Answer №4

One way to solve this problem is by using a temporary array to check the values for specific conditions.

We can create an array with some numbers and then define a temporary array where we will store certain values based on specific criteria. By iterating through the original array, we can determine which subset of values meets the required conditions and ultimately find the largest sequence that satisfies our constraints.

Answer 8

One way to solve this problem is by using a temporary array to check the values for specific conditions.

We can create an array with some numbers and then define a temporary array where we will store certain values based on specific criteria. By iterating through the original array, we can determine which subset of values meets the required conditions and ultimately find the largest sequence that satisfies our constraints.

Looking for assistance to find the largest sequence of 3 consecutive numbers within a string in javascript?

Answer №1

Answer №2

Answer №3

Answer №4

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