Locating the Index of a Line Break Starting from a Specified Position in JavaScript

Stored in my variable description is the following text:

`This is a code update`

Official Name: 2011 New York City Electrical Code

Code Tile Name:

Reference: https://www.nyc.gov/site/buildings/codes/electrical-code.page

Citation: §27-3024

Doc Title: Local Law 39-2011, Local Law 99-2013, Local Law 39-2015

Source Doc: https://www.nyc.gov/assets/buildings/pdf/ll39of2011_electrical_code.pdf

Drive: https://drive.google.com/file/d/19Q0_G3VITpx0iCULtANMHqydAv0ZmvcF/view?usp=share_link

Effective Date: November 19, 2013 


**SCTOMJ**

I am looking to extract the data associated with the phrase 

Official Name', specifically '2011 New York City Electrical Code
. To do this, I initially used the code snippet below:

var official_name = description.search("Official Name:"); 
if(official_name != -1){
    official_name = description.substring(official_name + 14, description.indexOf("Code Tile Name:")).trim();
}

The issue with the current code is that it relies on the fixed location of the phrase "Code Tile Name:", which is not ideal as the structure of the information may vary. I am seeking a solution that is not dependent on specific sequence.

Is there a method to locate the first newline character after a given position?

Thank you!

javascriptregexstring

Answer №1

Employ a look behind assertion to locate the line that initiates with "Official Name:". The string after the official name should encompass all characters excluding line breaks.

Note: utilize the multiline flag (/m) to ensure that the expression ^Official Name seeks the beginning of lines, not the entire text's start.

const str = `\`This is a code update\`

Official Name: 2011 New York City Electrical Code

Code Tile Name:

Reference: https://www.nyc.gov/site/buildings/codes/electrical-code.page

Citation: §27-3024

Doc Title: Local Law 39-2011, Local Law 99-2013, Local Law 39-2015

Source Doc: https://www.nyc.gov/assets/buildings/pdf/ll39of2011_electrical_code.pdf

Drive: https://drive.google.com/file/d/19Q0_G3VITpx0iCULtANMHqydAv0ZmvcF/view?usp=share_link

Effective Date: November 19, 2013 


**SCTOMJ**`

const result = str.match(/(?<=^Official Name:)[^\n\r]+/m)

console.log(result?.[0].trim())

Answer №2

Another option is to utilize a capture group:

^Official Name:[ \t]*(.+)

Clarification

  • ^ Indicates the start of the string
  • Official Name: Matches this literal phrase
  • [ \t]* Matches any optional spaces or tabs
  • (.+) Capture group 1, matching one or more characters excluding newlines

View Regex demonstration here

const s = `\`This is an update on the code\`

Official Name: 2011 New York City Electrical Code

Code Tile Name:

Reference: https://www.nyc.gov/site/buildings/codes/electrical-code.page

Citation: §27-3024

Doc Title: Local Law 39-2011, Local Law 99-2013, Local Law 39-2015

Source Doc: https://www.nyc.gov/assets/buildings/pdf/ll39of2011_electrical_code.pdf

Drive: https://drive.google.com/file/d/19Q0_G3VITpx0iCULtANMHqydAv0ZmvcF/view?usp=share_link

Effective Date: November 19, 2013 


**SCTOMJ**`

const m = s.match(/^Official Name:[ \t]*(.+)/m)
if (m)
  console.log(m[1]);

Answer №3

A solution is available.

The indexOf function requires two parameters, the first being the character to look for and the second indicating where to start the search.

indexOf(character_to_search, index_to_start_search)

Quick tip- Instead of manually entering 14 in your code, you can dynamically determine the length of the word "Official Name."

Check out this example-

const description = `\`This is a code update\`

Official Name: 2011 New York City Electrical Code

Code Tile Name:

Reference: https://www.nyc.gov/site/buildings/codes/electrical-code.page

Citation: §27-3024

Doc Title: Local Law 39-2011, Local Law 99-2013, Local Law 39-2015

Source Doc: https://www.nyc.gov/assets/buildings/pdf/ll39of2011_electrical_code.pdf

Drive: https://drive.google.com/file/d/19Q0_G3VITpx0iCULtANMHqydAv0ZmvcF/view?usp=share_link

Effective Date: November 19, 2013 


**SCTOMJ**`

var c = "Official Name:"
var official_name = description.search(c); 
if(official_name != -1){
    official_name = description.substring(official_name + c.length, description.indexOf("\n", official_name)).trim();
}
console.log(official_name)

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