Locating numerous occurrences of a specific string within an array and rearranging them

Question

Locating numerous occurrences of a specific string within an array and rearranging them

I am facing an issue with organizing data stored in the 'names' variable within the code snippet. The task at hand involves converting a string into an array, rearranging the elements within the array to ensure the text is in the correct order. While I have managed to successfully sort the first or last instance of a first & last name individually, I am now looking for guidance on how to handle multiple names efficiently. The current implementation only sorts the last occurrence of the first & last name correctly.

If we consider the input string:

names = "Bond, James & Banner, Bruce";

After processing, the expected output should be:

['James', 'Bond,', '&', 'Bruce', 'Banner,']

Your assistance and insights are highly appreciated. Thank you in advance!

Array.prototype.move = function(from,to){
  this.splice(to,0,this.splice(from,1)[0]);
  return this;
};

var names ="Bond, James & Banner, Bruce";

var namesArr = names.split(' ');
var idx;

// search for a comma (only last names have commas along with them)
for(var i = 0; i < namesArr.length; i++) {
  if(namesArr[i].indexOf(',') != -1) {
    idx = i;
  }
}
namesArr.move(idx, idx+1); 
console.log(namesArr);

javascript arrays sorting

Answer 1

Answer №1

You were very close to the solution in this case. All you need to do is update the loop and increment the index i to ensure that the switch is properly accounted for. Failure to do so may result in revisiting the first last name during the switch process.

Array.prototype.move = function(from,to){
  this.splice(to,0,this.splice(from,1)[0]);
  return this;
};

var names ="Bond, James & Banner, Bruce & Guy, Other";

var namesArr = names.split(' ');
var idx;

// Look for a comma (last names are the only ones with commas)
for(var i = 0; i < namesArr.length; i++) {
  if(namesArr[i].indexOf(',') != -1) {
    namesArr.move(i, i+1);
    i++; 
  }
}

console.log(namesArr);

Answer 2

You were very close to the solution in this case. All you need to do is update the loop and increment the index i to ensure that the switch is properly accounted for. Failure to do so may result in revisiting the first last name during the switch process.

Array.prototype.move = function(from,to){
  this.splice(to,0,this.splice(from,1)[0]);
  return this;
};

var names ="Bond, James & Banner, Bruce & Guy, Other";

var namesArr = names.split(' ');
var idx;

// Look for a comma (last names are the only ones with commas)
for(var i = 0; i < namesArr.length; i++) {
  if(namesArr[i].indexOf(',') != -1) {
    namesArr.move(i, i+1);
    i++; 
  }
}

console.log(namesArr);

Answer 3

Answer №2

One potential approach is to utilize the String.prototype.match() method along with a regular expression pattern like \w+ to extract and organize names:

var names = "Bond, James & Banner, Bruce & Licoln, Anna"; // ...
var arr_names = names.match(/\w+/g); // Extract individual names
var res = [];

for (var i = 0; i < arr_names.length; i += 2) { // Skip every other name
  res.push(arr_names[i + 1]); // Add the previous name
  res.push(arr_names[i]); // Add the current name
  res.push("&"); // Include "&"
}

res.splice((res.length - 1), 1); // Remove the last "&"
console.log(res);

Answer 4

One potential approach is to utilize the String.prototype.match() method along with a regular expression pattern like \w+ to extract and organize names:

var names = "Bond, James & Banner, Bruce & Licoln, Anna"; // ...
var arr_names = names.match(/\w+/g); // Extract individual names
var res = [];

for (var i = 0; i < arr_names.length; i += 2) { // Skip every other name
  res.push(arr_names[i + 1]); // Add the previous name
  res.push(arr_names[i]); // Add the current name
  res.push("&"); // Include "&"
}

res.splice((res.length - 1), 1); // Remove the last "&"
console.log(res);

Locating numerous occurrences of a specific string within an array and rearranging them

Answer №1

Answer №2

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