Locating conversation within a block of text using Javascript

Question

Locating conversation within a block of text using Javascript

Is there a way to extract dialogue, the content between quotes, from a paragraph in javascript and save it in an array?

var myParagraph = '
“Of course I’ll go Kate. You should get back to bed. Would you like some Nyquil or Tylenol?”
“Nyquil, please. Here are the questions and my mini-disc recorder. Just press record here. Make notes, I’ll transcribe it all.”
“I know nothing about him,” I murmur, trying and failing to suppress my rising panic. “The questions will see you through. Go. It’s a long drive. I don’t want you to be late.” “Okay, I’m going. Get back to bed. I made you some soup to heat up later.” I stare at her fondly. Only for you, Kate, would I do this.'

How can I split myParagraph to return an array like:

paragraphArray = ["Of course I’ll go Kate. You should get back to bed. Would you like some Nyquil or Tylenol?",
"Nyquil, please. Here are the questions and my mini-disc recorder. Just press record here. Make notes, I’ll transcribe it all.",
"I know nothing about him,",
"The questions will see you through. Go. It’s a long drive. I don’t want you to be late.",
"Okay, I’m going. Get back to bed. I made you some soup to heat up later."]

Thank you.

javascript arrays split nlp

Answer 1

Answer №1

const newParagraphArray = myParagraph.slice(1, myParagraph.length-2).split("”“");

This seems to be effective.

Answer 2

const newParagraphArray = myParagraph.slice(1, myParagraph.length-2).split("”“");

This seems to be effective.

Answer 3

Answer №2

Utilizing a regex pattern would be highly effective in this scenario. It is essential to ensure that the quotation marks within the string are standard " quotes, or you can adjust the regex to incorporate directional quotes instead. You have two options:

/"(.*?)"/ for regular quotes; or

/“(.*?)”/ for directional quotes.

The regex "(.*?)" specifically instructs to capture everything between two quote characters with a non-greedy search approach. Additionally, remember to include the g flag in the regex to retrieve all matches rather than just the initial one.

The method .match associated with strings receives a regex input and generates an array of matches. The structure of the resulting array varies depending on whether the regex included the g flag. As we are using said flag here, the output comprises an array of complete matches (inclusive of the surrounding quotes), prompting potential extraction of these quotes from each match result.

For a practical demonstration, consider the following:

var myParagraph = `
"Of course I’ll go Kate. You should get back to bed. Would you like some Nyquil or Tylenol?"
"Nyquil, please. Here are the questions and my mini-disc recorder. Just press record here. Make notes, I’ll transcribe it all."
"I know nothing about him," I murmur, trying and failing to suppress my rising panic. "The questions will see you through. Go. It’s a long drive. I don’t want you to be late." "Okay, I’m going. Get back to bed. I made you some soup to heat up later." I stare at her fondly. Only for you, Kate, would I do this.`

const rgx = /"(.*?)"/g;

const dialogue = myParagraph
    .match(rgx) // Utilize our defined regex pattern 
    .map(result => result.replace(/"/g, "")) // Eliminate quotes from each match result; delete this line if retaining the enclosing quotes is desired 

console.log(dialogue)

Answer 4

Utilizing a regex pattern would be highly effective in this scenario. It is essential to ensure that the quotation marks within the string are standard " quotes, or you can adjust the regex to incorporate directional quotes instead. You have two options:

/"(.*?)"/ for regular quotes; or

/“(.*?)”/ for directional quotes.

The regex "(.*?)" specifically instructs to capture everything between two quote characters with a non-greedy search approach. Additionally, remember to include the g flag in the regex to retrieve all matches rather than just the initial one.

The method .match associated with strings receives a regex input and generates an array of matches. The structure of the resulting array varies depending on whether the regex included the g flag. As we are using said flag here, the output comprises an array of complete matches (inclusive of the surrounding quotes), prompting potential extraction of these quotes from each match result.

For a practical demonstration, consider the following:

var myParagraph = `
"Of course I’ll go Kate. You should get back to bed. Would you like some Nyquil or Tylenol?"
"Nyquil, please. Here are the questions and my mini-disc recorder. Just press record here. Make notes, I’ll transcribe it all."
"I know nothing about him," I murmur, trying and failing to suppress my rising panic. "The questions will see you through. Go. It’s a long drive. I don’t want you to be late." "Okay, I’m going. Get back to bed. I made you some soup to heat up later." I stare at her fondly. Only for you, Kate, would I do this.`

const rgx = /"(.*?)"/g;

const dialogue = myParagraph
    .match(rgx) // Utilize our defined regex pattern 
    .map(result => result.replace(/"/g, "")) // Eliminate quotes from each match result; delete this line if retaining the enclosing quotes is desired 

console.log(dialogue)

Answer 5

Answer №3

If your text block lacks any instances of newline characters, then you have the option to utilize this method.

var myTextBlock = ' “Of course I’ll go Kate. You should get back to bed. Would you like some Nyquil or Tylenol?” “Nyquil, please. Here are the questions and my mini-disc recorder. Just press record here. Make notes, I’ll transcribe it all.” “I know nothing about him,” I murmur, trying and failing to suppress my rising panic. “The questions will see you through. Go. It’s a long drive. I don’t want you to be late.” “Okay, I’m going. Get back to bed. I made you some soup to heat up later.” I stare at her fondly. Only for you, Kate, would I do this.'; 

// captures everything enclosed by “ and ” excluding newline character
// '?' indicates non-greedy search
const regex = /“[^\n]*?”/g;
const result = [];
let match;

// continually push captured content into result array
while (match = regex.exec(myTextBlock)) {
  result.push(match[0]);
}

console.log(result);

You can also choose to eliminate the use of “ as shown in your query. By utilizing a capture group and pushing its contents into the resulting array instead.

var myTextBlock = ' “Of course I’ll go Kate. You should get back to bed. Would you like some Nyquil or Tylenol?” “Nyquil, please. Here are the questions and my mini-disc recorder. Just press record here. Make notes, I’ll transcribe it all.” “I know nothing about him,” I murmur, trying and failing to suppress my rising panic. “The questions will see you through. Go. It’s a long drive. I don’t want you to be late.” “Okay, I’m going. Get back to bed. I made you some soup to heat up later.” I stare at her fondly. Only for you, Kate, would I do this.'; 

// defines a capture group using `(, )`
const regex = /“([^\n]*?)”/g;
const result = [];
let match;
while (match = regex.exec(myTextBlock)) {
  // modified index number: 0 => 1
  result.push(match[1]);
}

console.log(result);

Answer 6

If your text block lacks any instances of newline characters, then you have the option to utilize this method.

var myTextBlock = ' “Of course I’ll go Kate. You should get back to bed. Would you like some Nyquil or Tylenol?” “Nyquil, please. Here are the questions and my mini-disc recorder. Just press record here. Make notes, I’ll transcribe it all.” “I know nothing about him,” I murmur, trying and failing to suppress my rising panic. “The questions will see you through. Go. It’s a long drive. I don’t want you to be late.” “Okay, I’m going. Get back to bed. I made you some soup to heat up later.” I stare at her fondly. Only for you, Kate, would I do this.'; 

// captures everything enclosed by “ and ” excluding newline character
// '?' indicates non-greedy search
const regex = /“[^\n]*?”/g;
const result = [];
let match;

// continually push captured content into result array
while (match = regex.exec(myTextBlock)) {
  result.push(match[0]);
}

console.log(result);

You can also choose to eliminate the use of “ as shown in your query. By utilizing a capture group and pushing its contents into the resulting array instead.

var myTextBlock = ' “Of course I’ll go Kate. You should get back to bed. Would you like some Nyquil or Tylenol?” “Nyquil, please. Here are the questions and my mini-disc recorder. Just press record here. Make notes, I’ll transcribe it all.” “I know nothing about him,” I murmur, trying and failing to suppress my rising panic. “The questions will see you through. Go. It’s a long drive. I don’t want you to be late.” “Okay, I’m going. Get back to bed. I made you some soup to heat up later.” I stare at her fondly. Only for you, Kate, would I do this.'; 

// defines a capture group using `(, )`
const regex = /“([^\n]*?)”/g;
const result = [];
let match;
while (match = regex.exec(myTextBlock)) {
  // modified index number: 0 => 1
  result.push(match[1]);
}

console.log(result);

Locating conversation within a block of text using Javascript

Answer №1

Answer №2

Answer №3

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