Locating a particular phrase within a collection of strings

When searching through an array of strings, a loop will return false if it encounters a string that does not match the criteria being looked for.

If no mismatches are found in the array, it should return true. However, even when there are no errors in the array, it continues to return false.

I have attempted various methods such as using indexOf, for loops, and while loops, but have had no success.

function checkBrackets() {
    var testArr = ['()', '{}', '()']

    /* Method 1 --- returns false even when the parentheses are correct, 
    likely due to indexOf only finding the first matching element */

    if (testArr.indexOf("()") == -1 || testArr.indexOf("{}") == -1 ||
        testArr.indexOf("[]") == -1) {
        return false
    } else {
        return true
    }

    /* Method 2 --- for loop. Also returns false despite all elements 
    complying with the conditions. It behaves strangely and I'm unsure why */

    for (i = 0; i < testArr.length; i++) {
        if (testArr[i] !== "()" || testArr[i] !== "{}" || testArr[i] !== "[]") {
            return false
        }
    }
    
    return true
}

checkBrackets()

Answer №1

The solution to this issue can be approached using the AND operator in the second method.

function checkBrackets() {
var testArray = ['()', '{}', '()'];

/* Method 2 --- for loop. Despite all elements of testArray matching any of the cases, the function still returns false. It seems to be treating them as not equal which is puzzling. */

for (let i = 0; i < testArray.length; i++) {
    if (testArray[i] !== "()" && testArray[i] !== "{}"  && testArray[i] !== "[]") {
        return false;
    }
}
return true;
}

checkBrackets();

Answer №2

Update your array to:

let newTestArr = ['()', '{}', '[]']

Because when you

 if (newTestArr.indexOf("()") == -1 || newTestArr.indexOf("{}") == -1 ||
        newTestArr.indexOf("[]") == -1)

Even if just one of these brackets is missing from the array, the condition will result in false.

Answer №3

A new array has been initialized

let exampleArray = ['()', '{}', '()']

To check the string, you will need to analyze the 2-dimensional array

if (exampleArray[0].includes("()") === -1)

Answer №4

Here is a solution that should work:

var testArr = ['()', '{}', '()'];

if(testArr.some(function(e){ return /(){}/g.test(e) })){
   console.log("Found the desired pattern");
} else {
   console.log("Pattern not found");   
}

This code snippet searches for all occurrences of "()" and "{}"

Link to demo

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