List of Years in JavaScript for a dropdown menu

Question

List of Years in JavaScript for a dropdown menu

I am working on implementing a dynamic select box in JavaScript that should display a range of years, starting from a specific year and ending with the current one. I'm curious if there is anything similar to Ruby's range class in JavaScript or if I'll have to iterate through the years using a for loop.

Here's my initial solution, but I feel like it may be overly complex compared to what could be achieved more easily in Ruby using a range.

    this.years = function(startYear){
        startYear = (typeof(startYear) == 'undefined') ? 1980 : startYear
        var currentYear = new Date().getFullYear();
        var years = []
        for(var i=startYear;i<=currentYear;i++){
            years.push(i);
        } 
        return years;
    }

javascript arrays range

Answer 1

Answer №1

Although JavaScript does provide a Range object, it is important to note that this object pertains to a random section of the DOM and unfortunately lacks support in IE 6/7.

If preferred, you can streamline your function like so, however, the result will remain largely unchanged.

this.years = function(startYear) {
    var currentYear = new Date().getFullYear(), years = [];
    startYear = startYear || 1980;  
    while ( startYear <= currentYear ) {
        years.push(startYear++);
    }   
    return years;
}
 
console.log( this.years(2019-20));

Answer 2

Although JavaScript does provide a Range object, it is important to note that this object pertains to a random section of the DOM and unfortunately lacks support in IE 6/7.

If preferred, you can streamline your function like so, however, the result will remain largely unchanged.

this.years = function(startYear) {
    var currentYear = new Date().getFullYear(), years = [];
    startYear = startYear || 1980;  
    while ( startYear <= currentYear ) {
        years.push(startYear++);
    }   
    return years;
}
 
console.log( this.years(2019-20));

Answer 3

Answer №2

Utilize the Array.from method

const presentYear = (new Date()).getFullYear();
const generateRange = (start, end, step) => Array.from({ length: (end - start) / step + 1}, (_, index) => start + (index * step));
console.log(generateRange(presentYear, presentYear - 50, -1)); 
// [2019, 2018, 2017, 2016, ..., 1969]

Answer 4

Utilize the Array.from method

const presentYear = (new Date()).getFullYear();
const generateRange = (start, end, step) => Array.from({ length: (end - start) / step + 1}, (_, index) => start + (index * step));
console.log(generateRange(presentYear, presentYear - 50, -1)); 
// [2019, 2018, 2017, 2016, ..., 1969]

Answer 5

Answer №3

This code snippet will create an array that begins with the current year and goes back in time by 50 years.

Array.from({ length: 51 }, (_, i) => new Date().getFullYear() - i);

If you need to modify the initial year, simply adjust

new Date().getFullYear()

To add years from the start instead of subtracting them, change the '-' to a '+'.

Answer 6

This code snippet will create an array that begins with the current year and goes back in time by 50 years.

Array.from({ length: 51 }, (_, i) => new Date().getFullYear() - i);

If you need to modify the initial year, simply adjust

new Date().getFullYear()

To add years from the start instead of subtracting them, change the '-' to a '+'.

Answer 7

Answer №4

Implement Array.fill() for modern browser compatibility and transpiling, without concern for older IE users.

const currentYear = new Date().getUTCFullYear();    
const yearsList = Array(currentYear - (currentYear - 20)).fill('').map((value, index) => currentYear - index);

// Returns: (20) [2019, 2018, 2017, 2016, 2015, 2014, 2013, 2012, 2011, 2010, 2009, 2008, 2007, 2006, 2005, 2004, 2003, 2002, 2001, 2000]

TypeScript

get years() {
  const currentYear = new Date().getUTCFullYear();
  return Array(currentYear - (currentYear - 20)).fill('').map((value, index) => currentYear - index) as Array<number>;
}

Answer 8

Implement Array.fill() for modern browser compatibility and transpiling, without concern for older IE users.

const currentYear = new Date().getUTCFullYear();    
const yearsList = Array(currentYear - (currentYear - 20)).fill('').map((value, index) => currentYear - index);

// Returns: (20) [2019, 2018, 2017, 2016, 2015, 2014, 2013, 2012, 2011, 2010, 2009, 2008, 2007, 2006, 2005, 2004, 2003, 2002, 2001, 2000]

TypeScript

get years() {
  const currentYear = new Date().getUTCFullYear();
  return Array(currentYear - (currentYear - 20)).fill('').map((value, index) => currentYear - index) as Array<number>;
}

Answer 9

Answer №5

If you are seeking a quick one-liner solution, you can utilize Array.from in just one line to generate a list of years.

var years = Array.from(Array(new Date().getFullYear() - 1949), (_, i) => (i + 1950).toString())
console.log(years)

This code will produce years from 1950 to the current year. It is compatible with all web browsers.

Answer 10

If you are seeking a quick one-liner solution, you can utilize Array.from in just one line to generate a list of years.

var years = Array.from(Array(new Date().getFullYear() - 1949), (_, i) => (i + 1950).toString())
console.log(years)

This code will produce years from 1950 to the current year. It is compatible with all web browsers.

Answer 11

Answer №6

To achieve this, combine Date() with Array.from():

getRecentYears = new Date().getFullYear(); // recent year
arrayOfYears = Array.from({length: 11}, (_, index) => this.getRecentYears - index);
console.log(arrayOfYears);
// Result: [2022, 2021, 2020, ...2012];

Answer 12

To achieve this, combine Date() with Array.from():

getRecentYears = new Date().getFullYear(); // recent year
arrayOfYears = Array.from({length: 11}, (_, index) => this.getRecentYears - index);
console.log(arrayOfYears);
// Result: [2022, 2021, 2020, ...2012];

Answer 13

Answer №7

This code snippet creates an array that starts from the current year and goes back 10 years.

Array.from({ length: 10 }, (_, i) => new Date().getFullYear() - i);
// => [2023, 2022, 2021, 2020, 2019, 2018, 2017, 2016, 2015, 2014, 2013]

Answer 14

This code snippet creates an array that starts from the current year and goes back 10 years.

Array.from({ length: 10 }, (_, i) => new Date().getFullYear() - i);
// => [2023, 2022, 2021, 2020, 2019, 2018, 2017, 2016, 2015, 2014, 2013]

Answer 15

Answer №8

While the solutions mentioned above are effective, I wanted to provide an additional answer for those who use lodash.

_.range([start=0], end, [step=1])

This function generates an array of numbers (positive and/or negative) starting from the 'start' value up to, but not including, the 'end' value.

I made sure to add 1 to the maximum value since lodash does not include the 'end' value in the range.

By implementing this, you can create an array representing years starting from 60 years ago up to the present year.

If you prefer the reverse order, you can utilize _.rangeRight.

const max = new Date().getUTCFullYear();
const min = max - 60;
const yearRange = _.range(min, max + 1);

console.log(yearRange);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.21/lodash.min.js"></script>

Answer 16

While the solutions mentioned above are effective, I wanted to provide an additional answer for those who use lodash.

_.range([start=0], end, [step=1])

This function generates an array of numbers (positive and/or negative) starting from the 'start' value up to, but not including, the 'end' value.

I made sure to add 1 to the maximum value since lodash does not include the 'end' value in the range.

By implementing this, you can create an array representing years starting from 60 years ago up to the present year.

If you prefer the reverse order, you can utilize _.rangeRight.

const max = new Date().getUTCFullYear();
const min = max - 60;
const yearRange = _.range(min, max + 1);

console.log(yearRange);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.21/lodash.min.js"></script>

Answer 17

Answer №9

    findYears(){
       var currentYear = new Date().getFullYear(),
       var years = [];
       var startYear = 1980;
       for(var i=startYear; i<= currentYear; i++){
          year.push(startYear++);
       }
       return years;
    }

Answer 18

    findYears(){
       var currentYear = new Date().getFullYear(),
       var years = [];
       var startYear = 1980;
       for(var i=startYear; i<= currentYear; i++){
          year.push(startYear++);
       }
       return years;
    }

Answer 19

Answer №10

let currentYear = new Date().getFullYear(); const yearsList = [...Array(currentYear - 1989).keys()].map((year) => year + 1990);

This code snippet creates an array containing the years from 1990 up to the current year (2021).

Answer 20

let currentYear = new Date().getFullYear(); const yearsList = [...Array(currentYear - 1989).keys()].map((year) => year + 1990);

This code snippet creates an array containing the years from 1990 up to the current year (2021).

Answer 21

Answer №11

Regrettably, JavaScript doesn't have a built-in "range" function like Ruby does, so you'll need to use a loop instead. Your current approach seems suitable for achieving the desired outcome.

Answer 22

Regrettably, JavaScript doesn't have a built-in "range" function like Ruby does, so you'll need to use a loop instead. Your current approach seems suitable for achieving the desired outcome.

Answer 23

Answer №12

If you're looking to create customized ranges in JavaScript, there's a handy range method that can help streamline your code. By utilizing this method effectively, you can efficiently generate arrays with specified intervals.

var X = Array.from(-3, 3) >>> output:

(Array) -3,-2,-1,0,1,2,3

var Y = Array.from(5, 50, 5) >>> output:

(Array) 5,10,15,20,25,30,35,40,45,50

var Z = Array.from('A', 'Z') >>> output:

(Array) A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z

Array.from = function(input, endValue, increment){
    var arr = [];
    if(arguments.length){
        if(endValue){
            return arr.range(input, endValue, increment);
        }
        let len = input.length;
        if(len){
            while(len){
                arr[--len] = input[len];
            }
            return arr;
        }
        if(input.hasOwnProperty){
            for(var prop in input){
                if(input.hasOwnProperty(prop)){
                    arr[arr.length] = input[prop];
                }
            }
            return arr;
        }
    }
    return arr;
}

Array.prototype.range = function(value, n, step){
    this[this.length] = value;
    if(value.split && n.split){
        value = value.charCodeAt(0);
        n = n.charCodeAt(0);
        while(value < n){
            this[this.length] = String.fromCharCode(++value);
        }
    } else if(isFinite(value)){
        step = step || 1;
        while(value < n) this[this.length] = value += step;
    }
    return this;
}

Answer 24

If you're looking to create customized ranges in JavaScript, there's a handy range method that can help streamline your code. By utilizing this method effectively, you can efficiently generate arrays with specified intervals.

var X = Array.from(-3, 3) >>> output:

(Array) -3,-2,-1,0,1,2,3

var Y = Array.from(5, 50, 5) >>> output:

(Array) 5,10,15,20,25,30,35,40,45,50

var Z = Array.from('A', 'Z') >>> output:

(Array) A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z

Array.from = function(input, endValue, increment){
    var arr = [];
    if(arguments.length){
        if(endValue){
            return arr.range(input, endValue, increment);
        }
        let len = input.length;
        if(len){
            while(len){
                arr[--len] = input[len];
            }
            return arr;
        }
        if(input.hasOwnProperty){
            for(var prop in input){
                if(input.hasOwnProperty(prop)){
                    arr[arr.length] = input[prop];
                }
            }
            return arr;
        }
    }
    return arr;
}

Array.prototype.range = function(value, n, step){
    this[this.length] = value;
    if(value.split && n.split){
        value = value.charCodeAt(0);
        n = n.charCodeAt(0);
        while(value < n){
            this[this.length] = String.fromCharCode(++value);
        }
    } else if(isFinite(value)){
        step = step || 1;
        while(value < n) this[this.length] = value += step;
    }
    return this;
}

List of Years in JavaScript for a dropdown menu

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

Answer №7

Answer №8

Answer №9

Answer №10

Answer №11

Answer №12

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