Could someone explain why the foo function functions properly?
function foo (x,y) {
return arguments.length;
}
However, when I call the boo function with arguments, it returns an error saying undefined is not a function.
function boo (c,d) {
return arguments.slice(0);
}
parameters are not arrays, but they behave like array objects. Numerous array functions can be used on these objects because they require an object with numerical properties and a size attribute, just like parameters. By using the call method and passing the object as the this parameter, you can utilize the built-in functions:
var values = Array.prototype.slice.call(parameters);
//^ values is now a genuine array
This technique also works with other methods, such as reduce:
function total(/*...values*/) {
return [].reduce.call(parameters, function(a, b){return a + b})
}
arguments is actually an object, not an array. When you print it out, you will see that it resembles an object:
function bar (x,y) {
console.log(arguments);
}
bar(30,40);
Output: { '0': 30, '1': 40 }
According to the information on this documentation,
This object has a specific entry for each argument passed into the function, starting with an index of 0. For example, if three arguments are passed into a function, they can be accessed like this:
arguments[0] arguments[1] arguments[2]
The object doesn't possess any properties commonly found in arrays except for length.
Therefore, trying to execute return arguments.slice(0); would result in an error because slice is associated with the prototype of an array.
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