Leveraging Javascript variables in console.log for referencing purposes

Question

Leveraging Javascript variables in console.log for referencing purposes

I have recently started learning JavaScript and I have a query regarding the usage of variables in the Console.log function.

What could possibly cause an error in this code snippet?

var myAns = console.log(65/240);
console.log(100* +Number(myAns) );

If I am storing the output of Console.log in the variable 'myAns', should I not be able to use it as a reference in another Console.log statement?

I tried using an additional + operator before the value (didn't work), or using the Number() method instead (also didn't work).

The error message that's being displayed is simply: NaN

Could this be because of pass by reference, or is it a scope-related issue?

javascript scope pass-by-reference pass-by-value

Answer 1

Answer №1

Is it possible to use the output of a console log as a reference in another console log if I assign it to a variable like 'myAns'?

To achieve this, you could either override the default console.log() function or simply do:

console.log(myAns = 65/240)

This means displaying the result of assigning 65/240 to myAns using console.log.

Currently, with var myAns = console.log(65/240);, you are actually assigning the return value of console.log(65/240) (which is undefined) to myAns, as pointed out by Bergi.

Answer 2

Is it possible to use the output of a console log as a reference in another console log if I assign it to a variable like 'myAns'?

To achieve this, you could either override the default console.log() function or simply do:

console.log(myAns = 65/240)

This means displaying the result of assigning 65/240 to myAns using console.log.

Currently, with var myAns = console.log(65/240);, you are actually assigning the return value of console.log(65/240) (which is undefined) to myAns, as pointed out by Bergi.

Answer 3

Answer №2

You've linked the return value of "console.log" to myAns. This doesn't give you the actual calculation result. What you should have is:

let myAns = 65 / 240;
console.log(myAns);
let myOtherResult = 100 * myAns;
console.log(myOtherResult);

Answer 4

You've linked the return value of "console.log" to myAns. This doesn't give you the actual calculation result. What you should have is:

let myAns = 65 / 240;
console.log(myAns);
let myOtherResult = 100 * myAns;
console.log(myOtherResult);

Answer 5

Answer №3

When a specific function includes a return statement with a return value, it will send back that value once the function is called from somewhere else.

The console.log function simply outputs the value provided within the parentheses to the browser.

Using console.log() does not assign a value to a variable... For example: var value = console.log(100); In this case, it only displays 100 in the browser without assigning anything to the 'value' variable.

Answer 6

When a specific function includes a return statement with a return value, it will send back that value once the function is called from somewhere else.

The console.log function simply outputs the value provided within the parentheses to the browser.

Using console.log() does not assign a value to a variable... For example: var value = console.log(100); In this case, it only displays 100 in the browser without assigning anything to the 'value' variable.

Leveraging Javascript variables in console.log for referencing purposes

Answer №1

Answer №2

Answer №3

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