If a synchronous function is called within the .then part of an asynchronous await .then, such as:
await asyncFunc(...)
.then(res => sendMSG(res))
.catch(err => next(err));
function sendMSG(res){
xyz
}
The sync function sendMSG is invoked in an asynchronous context. What would be the outcome if multiple asyncFunctions simultaneously invoke sendMSG?
What is the outcome of invoking a synchronous function within the .then part of an async await block?
The synchronous function will be executed.
What occurs when multiple asynchronous functions call sendMSG simultaneously?
JavaScript runs on an event loop where only one function can run at a time.
An asynchronous function will pause until its asynchronous task is complete. Once the event loop becomes available, it will resume processing the results of the async task and continue execution.
This process may delay other asynchronous functions from resuming their tasks until the ongoing one completes.
Due to its fundamental design, Javascript operates on a single thread, effectively ruling out the existence of multithreading concurrency where different sections of code are executed simultaneously on multiple threads.
Async functions (and even Promises) can be seen as merely a more user-friendly way of implementing callbacks in Javascript.
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