Learn the method of passing two parameters to the Onchange function within a select element

Here is my code snippet:

        <option value="">Select State</option>
                        <?php
         while($row=mysql_fetch_array($select))
         {
          echo "<option value=".$row['state_id'].">".$row['state']."     </option>";
         }
         ?>
                        </select>
                        </label>




                        <label style="margin-left:20px; width:200px; float:left; padding-top:6px;">

                        <select name="city" id="city" onChange="getArea('indexcontroller/indexmodules/findarea.php?city='+this.value)" style="width:220px;margin-left:3px;height:39px;margin-top:6px;">
                        <option value="">Select City/Town</option>
                        </select>

Is there a way to pass the selected state value to the getArea() function?

javascriptajax

Answer №1

Here's a way to achieve the desired result:

<select name="city" id="city" onChange="getArea('indexcontroller/indexmodules/findarea.php?city='+$('#StatedropDownId').val();)" style="width:220px;margin-left:3px;height:39px;margin-top:6px;">

Answer №2

To retrieve the value of a specific element, I would use its unique id attribute.

<select id="stateSelect">
    <option></option>
    <option></option>
    <option></option>
    <option></option>
    ...
</select>

<select id="citySelect" onchange="getArea('indexcontroller/indexmodules/findarea.php?state=' + document.getElementById('stateSelect').value + '&city='+this.value)">
    <option></option>
    <option></option>
    <option></option>
    <option></option>
    ...
</select>

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