JS Finding all individuals sharing a common last name

Question

JS Finding all individuals sharing a common last name

I recently started coding and came across this problem that I'm struggling to solve.

The task at hand is to create a function that takes an array of full names and returns only those with the last name "Smith".

  Example: ['Charlotte Jones', 'Rebecca Smith', 'Harry Smith', 'John Smithy', 'Smith Jones'] => ['Rebecca Smith', 'Harry Smith']

Here's the code I've written so far:

function getSmiths(arr) {
  return arr.filter(a =>a.includes("Smith"))
 }
 
 console.log(getSmiths(['Charlotte Jones', 'Rebecca Smith', 'Harry Smith', 'John Smithy', 'Smith Jones']));

I've tested my code with the following cases:

describe("getSmiths", () => {
  it("returns [] when passed []", () => {
    expect(getSmiths([])).to.eql([]);
  });
 it("returns a Smith from a mixed arrau", () => {
    expect(getSmiths(["Harry Smith", "Charlotte Bank"])).to.eql([
      "Harry Smith"
    ]);
  });
  it("returns multiple Smiths from a mixed array", () => {
    expect(getSmiths(["Harry Smith", "Charlotte Bank"])).to.eql([
      "Harry Smith"
    ]);
  });
  it("ignores Smiths found in first names", () => {
     expect(getSmiths(["Smithy Jones", "Harry     Smith"])).to.eql(["Harry Smith"]);
  });
  it("ignores Smiths found in extended last names", () => {
     expect(getSmiths(["John Smith", "Chris Smithy"])).to.eql(["John     Smith"]);
  });
});

Can anyone offer any insights as to why my code isn't working? Any suggestions would be greatly appreciated!

javascript arrays names arr

Answer 1

Answer №1

When utilizing the include function, it will search for the specific keyword within the entire string.

Utilizing the endsWith method:

let arr = ['Charlotte Jones', 'Rebecca Smith', 'Harry Smith', 'John Smithy', 'Smith Jones'];

    let result = arr.filter(element => element.endsWith('Smith'));

    console.log(result);

Using regex to filter results:

let arr = ['Charlotte Jones', 'Rebecca Smith', 'Harry Smith', 'John Smithy', 'Smith Jones'];

let result = arr.filter(element => /\ssmith$/ig.test(element));

console.log(result);

Answer 2

When utilizing the include function, it will search for the specific keyword within the entire string.

Utilizing the endsWith method:

let arr = ['Charlotte Jones', 'Rebecca Smith', 'Harry Smith', 'John Smithy', 'Smith Jones'];

    let result = arr.filter(element => element.endsWith('Smith'));

    console.log(result);

Using regex to filter results:

let arr = ['Charlotte Jones', 'Rebecca Smith', 'Harry Smith', 'John Smithy', 'Smith Jones'];

let result = arr.filter(element => /\ssmith$/ig.test(element));

console.log(result);

Answer 3

Answer №2

Have you identified which specific tests in the test group are showing failures?

The function you have created to extract array members containing the string 'Smith' will capture any items with 'Smith' anywhere in them and return the entire string.

In the 4th test within the group, both array items will be retrieved as they are stored (e.g., the second item will display as "Harry Smith").

Similarly, in your final test, both items will be returned, with the first one being presented as "John Smith".

To rectify this issue, modify your filter test to focus specifically on the last name by potentially splitting each string and evaluating against the last name only. You may need to figure out how best to implement this approach.

It appears that the last test is likely to fail based on the way it has been written. It seems like the intention was for it to return "John Smith" while ensuring that "Smithy" fails the test. Consider refining your filter criteria to match the last name EXACTLY to "Smith" rather than just including it.

Best of luck!

Answer 4

Have you identified which specific tests in the test group are showing failures?

The function you have created to extract array members containing the string 'Smith' will capture any items with 'Smith' anywhere in them and return the entire string.

In the 4th test within the group, both array items will be retrieved as they are stored (e.g., the second item will display as "Harry Smith").

Similarly, in your final test, both items will be returned, with the first one being presented as "John Smith".

To rectify this issue, modify your filter test to focus specifically on the last name by potentially splitting each string and evaluating against the last name only. You may need to figure out how best to implement this approach.

It appears that the last test is likely to fail based on the way it has been written. It seems like the intention was for it to return "John Smith" while ensuring that "Smithy" fails the test. Consider refining your filter criteria to match the last name EXACTLY to "Smith" rather than just including it.

Best of luck!

JS Finding all individuals sharing a common last name

Answer №1

Answer №2

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