JavaScript window.open not opening new window

Hey there, I'm currently working on logging into Twitter. Unfortunately, the window is not opening as expected in this code snippet. The response that is alerted isn't null and seems to be a link to a login screen. Any thoughts or suggestions on how to troubleshoot this issue?


var url = "./twitter_login.php";
var con = createPHPRequest();

con.open("POST",url,true);
con.setRequestHeader("Content-type","application/x-www-form-urlencoded");
con.send("");

var response = "";

con.onreadystatechange = function() {

    if(con.readyState==4 && con.status==200) {

        response = con.responseText;    
        alert(response);
        window.open(response,"twitter","menubar=1,resizable=1,width=350,height=500");        

    }

}
javascriptajaxtwitterwindow.open

Answer №1

Most modern browsers now come equipped with standardized popup-blocker logic that automatically blocks any attempts to use the window.open() function without direct user interaction. This means that code triggered by timers or asynchronous callbacks, such as AJAX ready functions, will typically be blocked as they are not considered user-initiated actions.

You can confirm this behavior by temporarily disabling your browser's popup blocker and observing that the functionality returns.

To work around this issue, consider creating the window at the moment of user interaction, then populating it with content upon receiving an AJAX response. This method is more likely to bypass the popup blocker restrictions. While it may not be visually ideal, you can display temporary content (e.g., "loading...") in the window until the response is received.

Answer №2

Recently encountered the same issue and found a solution that worked for me. Here's the code snippet I used:

newTab = window.open("", "_blank");

requestData = $.ajax({ ... my request to fetch a URL to load ... })

requestData.done((function(_this) {
        return function(data, status, xhr) {
          return newTab.location = data.Url;
        };
      })(this));

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