One interesting example in my code.
var array=[[1,'a'],[1,'b'],[2,'c'],[2,'b'],[2,'d'],[3,'a'],[3,'s'],[3,'w'],[3,'q'],[4,'w']]
Desired output is as below:
1 a
b
2 c
b
d
3 a
This code snippet replaces duplicate numbers with an empty string.
Attempting this approach, which only compares two elements at a time.
for( var i=0; i<array.length-1; i++ ) {
if ( array[i][0] == array[i+1][0] ) {
array[i+1][0]='';
}
}
In order to remove duplicate elements from an array, an external loop must be added:
for(var x=0; x < arr.length; x++){
for( var y=0; y<arr.length; y++ ) {
if ( arr[y][0] == arr[x][0] && y != x) {
arr[y][0]='';
}
}
}
The code provided below displays the data in the specified format without altering its content.
//display initial data
println( string(array[0][0]) + ' ' + array[0][1] )
var prevNumber = array[0][0] // keep track of the previously printed data number.
for( var i=1; i<array.length-1; i++ ) {
if ( array[i][0] == prevNumber ) { // if the number is the same, display ' ' instead of the number.
println( ' ' + ' ' + array[i][1] )
} else { // when the number changes
println( array[i][0] + ' ' + array[i][1] )
prevNumber = array[i][0] // update the previously printed data number.
}
}
Deleting a part of the data in an array is a simple task, but restoring deleted data later can be challenging or even impossible. This is the reason why the data in the array is left unmodified, and only the code for display is adjusted.
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