javascript regular expression that only matches strings with no characters preceding or following

Is there a way to change "me" to "you", except for when "me" is part of another word? For example, changing "awesome melon me" to "awesome melon you".

I've started using the negative look ahead pattern:

str.replace(/me(?![a-zA-Z])/g, 'you')

This results in:

"awesome melon me" -> "awesoyou melon you"

I have looked into different solutions on Stack Overflow, but haven't found one that fits my specific needs. Thank you in advance for any assistance!

Answer №1

One effective method is utilizing the special symbol \b to guarantee matching "me" only when it stands as a complete word:

"fantastic melon me".replace(/\bme\b/g, "you")
// yields "fantastic melon you"

Answer №2

Here is the solution: str.replace(\bme\b/g, 'you') - The symbol \b is used to search for a word boundary.

Answer №3

To keep the strings me345 or hello_me, you can implement word boundaries as suggested in previous responses. For a more precise matching pattern, consider capturing the letter before the desired sequence and including it in the replacement pattern.

var myString = "me awesome melon me"
console.log(myString.replace(/(^|[^a-zA-Z])(me)(?![a-zA-Z])/g, '$1you'));

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