I may have a partial solution to the problem. By the end, I just want the conclusion to be, "There are two names that begin with the letter B." I am currently not achieving this with my code below.
let count = 0;
let names = ["Bill", "Julia", "Coral", "Wendy", "Bob"];
for (let i = 0; i < names.length; i++) {
if (names[i].startsWith("B")) {
count++;
}
console.log("The letter B is at the beginning of " + count + " names");
}
There are a couple of issues in your code. First, you forgot to add a comma after declaring the variable 'count'. Secondly, the 'console.log()' statement is inside the loop, which means it will be executed multiple times. It should be placed outside the loop.
Here is the corrected code:
var count = 0,
names = ["Alice", "Bob", "Charlie", "David", "Eve"];
for (var i = 0; i < names.length; i++) {
if (names[i].startsWith("B")) {
count++;
}
}
console.log("Names starting with 'B': " + count);
Utilize the power of RegExp:
const people = ["Sara", "Mike", "Jack", "Emily", "Olivia"];
let startsWithLetter = (people, letter) => {
return people.filter(person => {
let pattern = new RegExp('^'+letter);
return person.match(pattern);
});
};
console.log(
'There are ' + startsWithLetter(people,"J").length + ' names that start with "J"',
startsWithLetter(people,"J")
);<script>
let counter = 0;
const names = ["Anna", "Sam", "Brianna", "William", "Brandon"];
for (let index = 0; index < names.length; index++) {
//The simple way is to check the first letter
if (names[index].substring(0)[0].match(/B/ig)) {
counter = counter + 1;
console.log(names[index].substring(0)[0] + " is at the beginning of " + names[index]);
}
}
//USUALLY OUTSIDE THE LOOP
//HERE YOU HAVE ALL THE MATCHED WORDS
if (counter > 0){
//Some names start with the letter B
//Remember to reset it at the end for reuse!
} else {
//No matches found...
}
</script>
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