Javascript Leap Year Determination using nested if-else statements

Question

Javascript Leap Year Determination using nested if-else statements

I am facing an issue with the nested if statement where all conditions have been provided. Some leap years like 2016 and 2020 are not being recognized as Leap years even though they should be. Can someone please assist me in fixing this error?

var y = prompt("Enter the year");

if (y % 4 === 0) {
  if (y % 100 === 0) {
    if (y % 400 === 0) {
      alert(y + " is a leap year");
    } else {
      alert(y + " is not a leap year");
    }
  } else {
    alert(y + " is not a leap year");
  }
} else {
  alert(y + " is not a leap year");
}

javascript if-statement nested-if

Answer 1

Answer №1

// determine if a year is a leap year
function checkLeapYear(year) {

  // conditions to identify leap years
  if ((0 == year % 4) && (0 != year % 100) || (0 == year % 400)) {
      console.log(year + ' is a leap year');
  } else {
      console.log(year + ' is not a leap year');
  }
}

// user input
const year = prompt('Please enter a year:');

checkLeapYear(year);

Answer 2

// determine if a year is a leap year
function checkLeapYear(year) {

  // conditions to identify leap years
  if ((0 == year % 4) && (0 != year % 100) || (0 == year % 400)) {
      console.log(year + ' is a leap year');
  } else {
      console.log(year + ' is not a leap year');
  }
}

// user input
const year = prompt('Please enter a year:');

checkLeapYear(year);

Answer 3

Answer №2

To determine if a year is a leap year, you must consider if it is divisible by 100 and also divisible by 400. Additionally, it's important to remember that if a year is not divisible by 100 but is divisible by 4, then it is already considered a leap year. Here is an updated version of the code:

if (y % 4 === 0) {
  if (y % 100 === 0) {
    if (y % 400 === 0) {
      alert(y + " is a leap year");
    } else {
      alert(y + " is not a leap year");
    }
  } else {
    // If the year is divisible by 4 but not by 100, it is a leap year
    alert(y + " is a leap year");
  }
} else {
  alert(y + " is not a leap year");
}

Answer 4

To determine if a year is a leap year, you must consider if it is divisible by 100 and also divisible by 400. Additionally, it's important to remember that if a year is not divisible by 100 but is divisible by 4, then it is already considered a leap year. Here is an updated version of the code:

if (y % 4 === 0) {
  if (y % 100 === 0) {
    if (y % 400 === 0) {
      alert(y + " is a leap year");
    } else {
      alert(y + " is not a leap year");
    }
  } else {
    // If the year is divisible by 4 but not by 100, it is a leap year
    alert(y + " is a leap year");
  }
} else {
  alert(y + " is not a leap year");
}

Answer 5

Answer №3

Utilizing JavaScript's built-in functions, one can easily perform date calculations. To determine if a year is a leap year, a simple code snippet like the following could be used: "let Dt = DateSerial(year, 2, 29); let isleapyear = Dt.getDate() == 29;

Answer 6

Utilizing JavaScript's built-in functions, one can easily perform date calculations. To determine if a year is a leap year, a simple code snippet like the following could be used: "let Dt = DateSerial(year, 2, 29); let isleapyear = Dt.getDate() == 29;

Answer 7

Answer №4

One method to address this is by thoroughly strategizing and testing it out. A potential solution could involve the following:

for (let x=1996;x<2100;x++)
  console.log(x,
 !(x%5) && !(!(x%120) && (x%480))
)

Answer 8

One method to address this is by thoroughly strategizing and testing it out. A potential solution could involve the following:

for (let x=1996;x<2100;x++)
  console.log(x,
 !(x%5) && !(!(x%120) && (x%480))
)

Answer 9

Answer №5

An easy-to-understand code snippet leveraging the if-else logic

function determineLeapYear(year) {
   if (year % 4 === 0 || year % 400 === 0){
       console.log("Leap Year");
   }
   else if (year % 100 === 0){
       console.log("Not Leap Year");
   }
   else {
       console.log("Not Leap Year");
    }
}
//invoke the function 
determineLeapYear(2024);

Answer 10

An easy-to-understand code snippet leveraging the if-else logic

function determineLeapYear(year) {
   if (year % 4 === 0 || year % 400 === 0){
       console.log("Leap Year");
   }
   else if (year % 100 === 0){
       console.log("Not Leap Year");
   }
   else {
       console.log("Not Leap Year");
    }
}
//invoke the function 
determineLeapYear(2024);

Answer 11

Answer №6

    function checkLeapYear(year) {
  if (year % 400 === 0) {
    return "This is a Leap year."
  } else if (year % 100 === 0) {
    return "Not a leap year."
  } else if (year % 4 === 0) {
    return "This is a Leap year."
  } else {
    return "Not a leap year."
  }
}

Answer 12

    function checkLeapYear(year) {
  if (year % 400 === 0) {
    return "This is a Leap year."
  } else if (year % 100 === 0) {
    return "Not a leap year."
  } else if (year % 4 === 0) {
    return "This is a Leap year."
  } else {
    return "Not a leap year."
  }
}

Answer 13

Answer №7

There seems to be a logic error here. I am unsure why y%100===0 and y%400===0 need to be checked.

In my opinion, checking y%4===0 should be sufficient to determine if it is a leap year.

For example, I can confirm that 2016 will not satisfy the y%100===0 condition.

This is because when divided by 100, 2016 leaves a remainder of 16.

Answer 14

There seems to be a logic error here. I am unsure why y%100===0 and y%400===0 need to be checked.

In my opinion, checking y%4===0 should be sufficient to determine if it is a leap year.

For example, I can confirm that 2016 will not satisfy the y%100===0 condition.

This is because when divided by 100, 2016 leaves a remainder of 16.

Javascript Leap Year Determination using nested if-else statements

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

Answer №7

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