JavaScript Indexed Array Names: Managing Arrays with Indices

Question

JavaScript Indexed Array Names: Managing Arrays with Indices

I have a collection of arrays named "list0" through "list7" which have been explicitly defined. My goal is to include each of these arrays as elements in an existing array, creating a 2D array of these defined arrays.

How can I reference each 'list' array in a 'for' loop?

For example:

var matrix1 = new Array();

function makeMatrix1(){

    for(row=0; row<8; row++)
    {       

        matrix1[row] = list[row]//put each 'list' array into matrix1 as an element

    }

The above syntax is not functioning correctly, for obvious reasons.

javascript arrays names

Answer 1

Answer №1

What do you think of this approach?

const matrix1 = [list0, list1, list2, list3, list4, list5, list6, list7];

It's a different way of doing it compared to a traditional for loop, but it seems straightforward and effective. I personally prefer this method over using eval in situations like this.

const matrix1 = [];
for (let row = 0; row < 8; row++) {
    matrix1.push(eval("list" + row));
}

Answer 2

What do you think of this approach?

const matrix1 = [list0, list1, list2, list3, list4, list5, list6, list7];

It's a different way of doing it compared to a traditional for loop, but it seems straightforward and effective. I personally prefer this method over using eval in situations like this.

const matrix1 = [];
for (let row = 0; row < 8; row++) {
    matrix1.push(eval("list" + row));
}

Answer 3

Answer №2

If you want to achieve a similar result, try the following:

   let myTwoDimArray = [list1,........,list7];

Then, to display the first element:

   alert(myTwoDimArray[0][0]);

I hope this solution is useful to you.

Answer 4

If you want to achieve a similar result, try the following:

   let myTwoDimArray = [list1,........,list7];

Then, to display the first element:

   alert(myTwoDimArray[0][0]);

I hope this solution is useful to you.

Answer 5

Answer №3

Arrays like list0, list1, list2, etc., are already organized in a structured format. What if we did the following:

list=new Array();
list[0]=["a","b","c"];
list[1]=["d","e"];
list[2]=["f","g","h","j"];
and so on

This would essentially create a matrix structure. Since rows are explicitly defined, we can also set it up like this:

matrix=new Array();
matrix[0]=["a","b","c"];
matrix[1]=["d","e"];
matrix[2]=["f","g","h","j"];
and so on

Accessing elements within the matrix would be as simple as matrix[1][1] giving "e" and matrix[2][3] giving "j", and so forth.

Alternatively, we could simplify the process by directly creating the matrix as shown below:

matrix=[
   ["a","b","c"],
   ["d","e"],
   ["f","g","h","j"],
   .....
   .....
   and so on for each of the 8 rows
]

This approach would yield the same result.

Answer 6

Arrays like list0, list1, list2, etc., are already organized in a structured format. What if we did the following:

list=new Array();
list[0]=["a","b","c"];
list[1]=["d","e"];
list[2]=["f","g","h","j"];
and so on

This would essentially create a matrix structure. Since rows are explicitly defined, we can also set it up like this:

matrix=new Array();
matrix[0]=["a","b","c"];
matrix[1]=["d","e"];
matrix[2]=["f","g","h","j"];
and so on

Accessing elements within the matrix would be as simple as matrix[1][1] giving "e" and matrix[2][3] giving "j", and so forth.

Alternatively, we could simplify the process by directly creating the matrix as shown below:

matrix=[
   ["a","b","c"],
   ["d","e"],
   ["f","g","h","j"],
   .....
   .....
   and so on for each of the 8 rows
]

This approach would yield the same result.

JavaScript Indexed Array Names: Managing Arrays with Indices

Answer №1

Answer №2

Answer №3

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