I'm attempting to extract the odd numbers from the given array and then double them using the reduce method, but I keep getting an undefined error. Can someone please offer some guidance?
const multiplyOddByTwo = (arr) => {
return arr.reduce((acc, curr) => {
if (curr % 2 === 0) {
arr.push(curr);
} else {
arr.push(curr * 2)
}
}, [])
}
console.log(multiplyOddByTwo([1, 2, 3]));Here are a couple of pointers to consider:
const multiplyOddByTwo = (arr) => {
return arr.reduce((acc, curr) => {
if (curr % 2 === 0) {
acc.push(curr);
} else {
acc.push(curr * 2)
}
return acc;
}, [])
}
console.log(multiplyOddByTwo([1, 2, 3])); // [2,2,6]
This function multiplies odd-indexed elements by 2.
Note: The result isn't an undefined error, it's simply the return of undefined. Any function that doesn't explicitly return something will default to returning undefined.
To exclusively retrieve odd numbers multiplied by 2 and not include the even numbers, you can utilize this code:
const multiplyOddByTwo = (arr) => {
const odd = arr.filter(num => num % 2 !== 0);
return odd.map(i => i * 2);
}
console.log(multiplyOddByTwo([1, 2, 3]));If you prefer all numbers to be returned but only odd numbers should be multiplied by 2, then you can use this code:
const multiplyOddByTwo = (arr) => {
return arr.map(num => num % 2 === 0 ? num : num * 2);
}
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