Could anyone help me figure out why my code is now returning null when it used to find a match? I want it to search for a match in the string for 1 hour.
var error = "null";
var str = "1 hour"
var strCheck = str.match(/[1]\s[hour]\s/g);
if(String(strCheck) != error) {
alert("It works!");
}
Take a look at this..
var error = "null";
var str = "1 hour "
var strCheck = str.match(/1 hour /g);
if(strCheck != error) {
alert("works!");
}Explanation:
[] is used to match a single character so [hour] is not correct and if you have change in number of hours you can make it like this:
var error = "null";
var str = "1 hour "
var strCheck = str.match(/[0-9][0-9] hour /g);
if(strCheck != error) {
alert("works!");
}or Simply use \d to find a digit and \d+ to find one or more digit.
For more see this its simple and clear.
The regular expression pattern [1]\s[hour]\s is not suitable for this task. The character class [] without quantifiers is designed to match only a single character from the specified characters. Therefore, [hour] will match one of the characters - h, o, u, or r. If you want to match the word "hour" as a complete string, a different approach is needed.
To create a more dynamic regex pattern that can even match expressions like "10 hours," the following regex can be used:
/\d+\s*hours?\s*/Code:
var error = "null";
var str = "1 hour ";
var strCheck = str.match(/\d+\s*hours?\s*/g);
if (strCheck != null) {
alert("works!");
}
console.log(strCheck);If the goal is to simply check if the string contains a specific pattern, it's recommended to use RegExp#test instead of String#match.
/\d+\s*hours?\s*/.test(str)Not sure what type of validation you are looking for using that regex pattern, but this example could be helpful:
\d+\s(hour(s)?)
Explanation:
\d+ Represents one or more digits\s Signifies a blank space(hour(s)?) Represents the word hour with an optional letter s at the end for plurality.The match() method will return an array of results or null if no match is found. My suggestion is to simply check the result as a boolean value instead of comparing it to a "null" string. Your code could look something like this:
var strCheck = str.match(/\d+\s(hour(s)?)/, g);
if (strCheck) {
alert("It works!");
}
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