Can anyone help me determine whether 'buns' or 'duns' has the most elements in common with 'me'? I need a method to accomplish this task.
var buns = ['bap', 'bun', 'bop'];
var duns = ['dap', 'dun', 'dop'];
var me = ['dap', 'bun', 'bop'];
Can anyone help me determine whether 'buns' or 'duns' has the most elements in common with 'me'? I need a method to accomplish this task.
var buns = ['bap', 'bun', 'bop'];
var duns = ['dap', 'dun', 'dop'];
var me = ['dap', 'bun', 'bop'];
Iterate through the given array and check if each item exists in another array called me.
function findCommonElements(arr1, arr2) {
return arr2.reduce(function (previous, current) {
if (arr1.indexOf(current) > -1) previous++;
return previous;
}, 0);
}
findCommonElements(me, buns); // 2
findCommonElements(me, duns); // 1
Essential Index Comparison
function checkIndex(a, b) {
return a.reduce((total, item, i) => {
if (item !== b[i]) return total + 1;
return total;
}, 0);
}
Non-critical Index, Ignoring Duplicates
function compareValues(a, b) {
return a.reduce((total, item, i) => {
if (b.indexOf(item) === -1) return total + 1;
return total;
}, 0);
}
Disregarding Index, Acknowledging Duplicates
function similarItems(a, b) {
b = b.slice();
return a.reduce((total, item, i) => {
let j = b.indexOf(item);
if (j === -1) return total + 1;
b.splice(j, 1);
return total;
}, 0);
}
The lower score signifies high similarity, for example:
compareValues(apples, bananas) // 1
compareValues(apples, oranges) // 2
// `bananas` bear more resemblance to `apples` than `oranges`
Keep in mind these operations are not interchangeable when the array lengths differ; checkIndex(a, b) may yield different results compared to checkIndex(b, a) with unequal lengths: a.length !== b.length
For accurate comparisons, ensure the shared array is placed consistently in all tests
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