Iterate through Array(n) using the forEach method, which loops over an array consisting of undefined

I'm interested in efficiently creating an array of a specific length using the Array() constructor and then iterating over it.

According to the information on MDN:

If you pass only an integer between 0 and 232-1 (inclusive) as the argument to the Array constructor, it will return a new JavaScript array with the length set to that number. Any other argument will result in a RangeError exception being thrown.

For example, executing Array(5) does indeed create an array with a length of 5.

var arr = new Array(5);

console.log(arr); // [undefined x 5]
console.log(arr.length); // 5

However, when attempting to iterate over the elements of this array using forEach, nothing is logged to the console.

arr.forEach(function(v, i) { console.log(v, i); });

// nothing logs to the console

In contrast, if I use an array literal and loop over the values, the expected output is logged:

[undefined, undefined].forEach(function(v, i) { console.log(v, i); });

// undefined 0
// undefined 1

Why does the forEach loop not work with arrays created by the Array constructor?


This answer sheds some light on the peculiar behavior observed with map, for instance:

arr.map(function(v, i) { return i; }) // returns [undefined x 5]

However, my main focus is on understanding why the forEach loop fails to iterate over the values at all.

Answer №1

Although I may not be directly answering the question, I believe that the information I provide is valuable.

Take a look at what Kyle Simpson recently discussed regarding this topic.

In essence,

console.log(new Array(5))  // Chrome: [undefinedx5] Firefox: [ <5 empty slots> ]

and

console.log([undefined, undefined, undefined, undefined, undefined]) // [ undefined, undefined, undefined, undefined, undefined ] 

are actually different value types. When the browser displays 'undefinedx5', it's not entirely accurate. In the first case, using .map() will return nothing, while in the second case you can perform operations with the undefined values.

As per the spec, ecma-262/5.1/#sec-15.4.2.2, the function new Array(5) simply creates an Array object with a length property of 5. On the other hand, when using the array literal syntax, [], it places actual types (if provided) into the array slots.

Answer №2

The reason for this behavior is that ES5 array methods will skip over missing indexes. This means they iterate through values of i from 0 to length-1, but at each iteration, they check if the array actually has a property at that index.

To ensure it works as expected, you can use the fill method to create the necessary indices.

var newArr = new Array(5).fill();
newArr.forEach(function(value, index) { console.log('newArr['+index+'] = ' + value); });

Answer №3

Seems like a minor mistake is in your code:

arr.forEach(functio(v, i) {

To correct it, use the following instead:

arr.forEach(function(v, i) {

UPDATE

The forEach() function runs the specified callback once for each element in the array in ascending order. It does not work on index properties that have been removed or are uninitialized (such as with sparse arrays). MDN article

Answer №4

My theory is that the issue lies in the complexities of the Javascript foreach loop, rather than with the Array(int) constructor. When implementing a standard for loop instead:

for(var i = 0; i < arr.length; i += 1) {
  console.log(arr[i] + " " + i);
}

The outcome met expectations.

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