Look at the code provided:
const {
aForm,
bForm,
eForm,
qForm,
} = this.form;
return (
aForm.isEditing ||
bForm.isEditing ||
eForm.isEditing ||
qForm.isEditing
);
Can we optimize this in a different way? Perhaps something like this:
const forms = pick(this.form, [
"aForm",
"bForm",
"eForm",
"qForm",
]);
Object.values(forms).map(f => f.isEditing).join("||") //Need to return boolean value.
In my opinion, the existing setup you have is pretty close to what most viewers would expect. I recommend utilizing Array#some for this task. It allows you to verify if at least one of the items meets the specified condition (similar to a logical OR ||).
Your current function functions in the opposite manner as it checks each value with every item (resembling a logical AND &&).
const properties = [
"aForm",
"bForm",
"eForm",
"qForm",
]
return properties.some(prop => {
const obj = this.form[prop] // Retrieve your form element
return obj.isEditing;
})
let formArray = [
"aForm",
"bForm",
"eForm",
"qForm",
];
const result = Object.values(formArray).map(form => eval(form).isEditing).join("||");
eval(result);
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