Iterate through an array, mapping the values and then returning a

Look at the code provided:

const {
      aForm,
      bForm,
      eForm,
      qForm,
    } = this.form;

return (
      aForm.isEditing ||
      bForm.isEditing ||
      eForm.isEditing ||
      qForm.isEditing
    );

Can we optimize this in a different way? Perhaps something like this:

const forms = pick(this.form, [
      "aForm",
      "bForm",
      "eForm",
      "qForm",
    ]);
Object.values(forms).map(f => f.isEditing).join("||") //Need to return boolean value.

Answer №1

In my opinion, the existing setup you have is pretty close to what most viewers would expect. I recommend utilizing Array#some for this task. It allows you to verify if at least one of the items meets the specified condition (similar to a logical OR ||).

Your current function functions in the opposite manner as it checks each value with every item (resembling a logical AND &&).

const properties = [
  "aForm",
  "bForm",
  "eForm",
  "qForm",
]

return properties.some(prop => {
  const obj = this.form[prop] // Retrieve your form element

  return obj.isEditing;
})

Answer №2

let formArray = [
  "aForm",
  "bForm",
  "eForm",
  "qForm",
];
const result = Object.values(formArray).map(form => eval(form).isEditing).join("||");
eval(result);

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