Issues with utilizing indexOf function on an intricate array

Similar Question:
Finding Index of an Object in JavaScript Array

In my code, I have a JavaScript array structured like this:

var userList = [
{id: "a", gender: "man",   item: "stuff"},
{id: "b", gender: "woman", item: "stuff"},
{id: "c", gender: "man",   item: "stuff"},
{id: "d", gender: "man",   item: "stuff"}
];

I am looking for a way to utilize the indexOf method to find the index in the array based on a specific variable such as the "id".

For instance, I attempted the following:

var index = userList.indexOf("b");
userList[index].gender = "man";

Currently, I am resorting to:

for(var i=0; i<userList.length; i++) {
   if(userList[i].id == "b"){
       userList[i].gender = "man";
   }
}

The loop method works fine, but with a large array like mine containing 150 entries and 10 items each, looping through it all is inefficient when I already know the "id" of the entry. Implementing indexOf would offer a cleaner solution if I can make it work.

Answer №1

The method you are using, indexOf, to search for objects in your array based on a string comparison with 'b' will not work.

A simple solution is to loop through the array elements to find the correct id.

Another option is to create your own custom indexOf function:

Array.prototype.indexOfId = function(id) {
    for (var i = 0; i < this.length; i++)
        if (this[i].id === id)
            return i;
    return -1;
}

    var arrayName = [
      { id: "a", gender: "man", item: "stuff" },
      { id: "b", gender: "woman", item: "stuff" },
      { id: "c", gender: "man", item: "stuff" },
      { id: "d", gender: "man", item: "stuff" }];

    var position = arrayName.indexOfId("b");

    alert(position);  //alerts 1

Check out this helpful fiddle

EDIT

If you would like to compare array elements based on any property value, follow these steps (using [] notation to access arbitrary properties)

    Array.prototype.indexOfField = function (propertyName, value) {
        for (var i = 0; i < this.length; i++)
            if (this[i][propertyName] === value)
                return i;
        return -1;
    }

    var position = arrayName.indexOfField("id", "b");
    alert(position);  //alerts 1

    position = arrayName.indexOfField("gender", "man");
    alert(position); //alerts 0

Alternatively, if you prefer not to modify the Array prototype and do not mind using modern browser features, you can utilize the filter function of Arrays

var position = arrayName.indexOf(arrayName.filter(function (val) {
      return val.id === "b";
})[0]);

Note that this approach may not be compatible with older browsers such as IE8. For IE support, consider obtaining the necessary shim from MDN here

EDIT - It seems that indexOf may also pose compatibility issues with older browsers. If you choose to implement the second code snippet, ensure to include a shim for indexOf from this source here

Answer №2

If the chance presents itself, you can utilize Array.prototype.filter:

var listOfItems = [
    {id: "a", gender: "man",   item: "stuff"},
    {id: "b", gender: "woman", item: "stuff"},
    {id: "c", gender: "man",   item: "stuff"},
    {id: "d", gender: "man",   item: "stuff"}
];

console.log(listOfItems.filter(function(item) {
    return item.id === 'b';
}));

This will result in:

[ { id: 'b', gender: 'woman', item: 'stuff' } ]

Answer №3

By utilizing the prototype, you have the ability to override the indexOf method.

Array.prototype.indexOf = function(elem) {
    for (var i = 0; i < this.length; i++){
        if (this[i].id === elem)
            return i;
    }
    return -1;
}

var arrayName = [
{id: "a", gender: "man",   item: "stuff"},
{id: "b", gender: "woman", item: "stuff"},
{id: "c", gender: "man",   item: "stuff"},
{id: "d", gender: "man",   item: "stuff"}
];

alert(arrayName.indexOf("b"));

fiddle : http://jsfiddle.net/r8rp9/1/

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