Can you determine the time complexity of this code snippet? response: O(log2n) explanation: By looping with i=0; while i is less than n; incrementing i*2, the loop continues indefinitely until the condition becomes false
Can you determine the time complexity of this code snippet? response: O(log2n) explanation: By looping with i=0; while i is less than n; incrementing i*2, the loop continues indefinitely until the condition becomes false
Your code is stuck in an infinite loop because you are multiplying zero in your incremental expression without updating the value of the variable i.
This means that the condition you've set will always be true.
To fix this, you need to make sure to actually increment your i within the loop.
Here's an example of how your incremental expression should look:
i *= 2
Instead of just multiplying by 2 like this:
i * 2
If you want to start with i at 0 initially but still avoid an infinite loop, you need to increment it within the scope of your for loop.
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