Let's say I have the following JavaScript code snippet:
let num = 00111;
console.log(num.toString());
Executing this code would result in '73' being displayed.
However, my desired output is to see '00111' instead of '73.'
Let's say I have the following JavaScript code snippet:
let num = 00111;
console.log(num.toString());
Executing this code would result in '73' being displayed.
However, my desired output is to see '00111' instead of '73.'
The reason behind the unexpected number result lies in the presence of leading 0s in an integer literal, which signals to JavaScript that the number is an octal literal with a radix of 8.
To achieve the desired outcome, you have two options: either eliminate the leading zeros from the literal and add them back later like this:
let num = 111;
console.log('00' + num.toString());
Alternatively, you can store the value as a string and then parse it like so:
let value = '00111':
let num = parseInt(value); // assumes radix 10.
console.log('00' + num.toString());
If the objective is simply to count the bits represented by the 1s (which could explain the '3' in the example), you can create a helper function that counts the number of 1s in a string and use that to retrieve the value, as demonstrated here.
However, if the aim is to represent a binary number literally (7 instead of 3), you can utilize binary literals like this:
let num = 0b00111;
console.log(num); // 7
console.log(num.toString(2)); // 111
When using the Number.prototype.toString() method in JavaScript, you can specify a radix parameter to convert your number to a string in that particular base.
For example, if you want to represent a number in its octal notation, you can achieve this by:
let num = 00111;
let str = `00${num.toString(8)}`;
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