Is there a way to substitute the final character in the specific regex I've selected?

I have a specific string that I need to modify from {Rotation:[45f,90f],lvl:10s} to {Rotation:[45,90],lvl:10}.

Here is the code I tried:

const bar = `{Rotation:[45f,90f],lvl:10s}`
const regex = /(\d)\w+/g
console.log(bar.replace(regex, '$&'.substring(0, -1)))

I also attempted to extract the last character using $ but it hasn't been successful so far.

Answer №1

If you want to use a regular expression pattern to manipulate strings in JavaScript, you can try the following code:

bar.replace(/(\d+)[a-z]\b/gi, '$1')

To see how this regex works, check out the demo here.

In the regex pattern:

  • (\d+) - captures one or more digits into Group 1
  • [a-z] - matches any letter
  • \b - specifies a word boundary, indicating the end of a word
  • gi - performs a global search (all occurrences) and is case insensitive

The replacement value is taken from Group 1 using $1.

You can test this functionality with the JavaScript demo below:

const bar = `{Rotation:[45f,90f],lvl:10s}`
const regex = /(\d+)[a-z]\b/gi
console.log(bar.replace(regex, '$1'))

Answer №2

Take a look at this:

let sentence = `The quick brown fox jumps over the lazy dog`.split(' ');
const removedWord = sentence.splice(sentence.length - 3, 1);
console.log(sentence.join(' '));

Answer №3

To avoid capturing the closing brace, you can utilize positive lookahead in your regex pattern. By doing this, you can easily replace the single character with an empty string.

const foo = '{Rotation:[45f,90f],lvl:10s}'
const regexPattern = /.(?=})/g
console.log(foo.replace(regexPattern, ''))
{Rotation:[45f,90f],lvl:10}

Answer №4

This particular regular expression is designed to identify any sequence of one or more digits followed by either 'f' or 's'.

When using $1, it refers to the captured content within the parentheses of (\d).

const example = `{Rotation:[45f,90f],lvl:10s}`
const pattern = /(\d+)[fs]/g
console.log(example.replace(pattern, '$1'))

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