Is there a way to prevent the omission of zeros at the end in JavaScript when using Number.toString(2)?

I am facing an issue while trying to reverse a 32-bit unsigned integer by converting it to a string first. The toString(2) function is causing the zeros at the end to be omitted, leading to incorrect output.

This is my code:

var reverseBits = function(n) {
    let reverserN=(n>>>0).toString(2).split('').reverse().join('');
    console.log(reverserN)
    
    return parseInt(reverserN,2)
};

Here's the current output:

Your input 00000010100101000001111010011100

stdout 00111001011110000010100101 //End zeros are missing

Output

15065253 (00000000111001011110000010100101)

Expected

964176192 (00111001011110000010100101000000)

Additionally, attempting to use BigInt results in the character 'n' being added to the end of the reversed bits as shown here: 00111001011110000010100101n.

Why are the zeros being omitted? And how can I prevent this from happening?

Answer №1

When you include padEnd(32,0) right after join(''), it does the job perfectly. This function adds zeros at the end of the resulting string to match a specific length.

This is what my code looks like:

var reverseBits = function(n) {
    let reversedN=(n>>>0).toString(2).split('').reverse().join('').padEnd(32,0);
    console.log(reversedN);
    return parseInt(reversedN,2)
};

The output will be:

00111001011110000010100101000000 // 6 zeros at the end of the string

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