Looking for a way to separate even and odd numbers into two arrays? This function will do just that, but with a twist - the evens array will be printed before the odds.
var numbersArray = [1,2,34,54,55,34,32,11,19,17,54,66,13];
function customDivider(numbersArray) {
var evensOdds = [[], []];
for (var i = 0; i < numbersArray.length; i++) {
evensOdds[i & 1].push(numbersArray[i]);
}
return evensOdds;
}
If you're looking to categorize numbers based on their even and odd values, instead of relying solely on the index (id), consider using the value itself - numbersArray[i] % 2.
const numbersArray = [1, 2, 34, 54, 55, 34, 32, 11, 19, 17, 54, 66, 13];
function segregator(numbersArray) {
const evensOdds = [[], []];
for (let i = 0; i < numbersArray.length; i++) {
evensOdds[numbersArray[i] % 2].push(numbersArray[i]);
}
return evensOdds;
}
console.log(segregator(numbersArray));If you wish to divide them by even and odd indexes, use (i + 1) % 2 to identify the correct sub array:
const numbersArray = [1, 2, 34, 54, 55, 34, 32, 11, 19, 17, 54, 66, 13];
function segregator(numbersArray) {
const evensOdds = [[], []];
for (let i = 0; i < numbersArray.length; i++) {
evensOdds[(i + 1) % 2].push(numbersArray[i]);
}
return evensOdds;
}
console.log(segregator(numbersArray));Just for kicks, here's a forEach variation of the solution that was approved.
let numsArr = [1,2,34,54,55,34,32,11,19,17,54,66,13];
let even_odd = [ [], [] ];
numsArr.forEach( num => even_odd[num % 2].push(num) );
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