Is there a way to display all the files within an archive while excluding the use of "*" in the 7-Zip command line?

Is there a way to display all the files and folders in an archive using the 7-Zip command line, while excluding '*' from the list using regular expression? I am trying to identify the number of folders at the first level of the archive (such as xxx\ or xxx, but not xxx\abc).

In the list of the archive, I want to match the last three items and then exclude them, while still keeping the first one:
xxx<br> xxx\123.txt
xxx\abc
xxx\abc\456.pdf

I attempted to achieve this using 7z l archive.zip -x!*\*, but it ended up excluding the first item xxx\.

Update: I am currently using *\?* as a temporary solution to filter out the outputs.

Answer №1

z-zip does not rely on regular expressions or OS wildcards; instead, it utilizes a simplified range of switches for filenames.

An important point to note is that while some zip files may contain empty folder entries, the majority do not. They simply store filenames with their corresponding path names, making it difficult to list folder names independent of file wildcard entries.

The solution to your problem lies in filtering the output of fuller filenames to extract the specific text you need. This task might be easier to accomplish on Linux compared to Windows due to the complexity of dealing with loops in the latter operating system.

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