Imagine I am working with a collection that contains 3 items:
[
{
id: 'x',
elements: [10, 20, 30]
}, {
id: 'y',
elements: [40, 50, 60]
}, {
id: 'z',
elements: [70, 80, 90]
}
]
In my JavaScript code, I have an array [50, 20, 60, 40, 70, 80]. How can I construct a query to specifically choose the second object from the collection since my array includes all the numbers (40, 50, and 60) in its elements array?
One way to filter an array using mongoDB is by utilizing the Aggregation Set Operator. This involves finding the intersection of the given array with the database array and then checking for equality using the setEquals method. See the example query below:
db.collectionName.aggregate({
"$project": {
"checkAllElem": {
"$setEquals": [{
"$setIntersection": ["$items", [5, 2, 6, 4, 7, 8]]
}, "$items"]
},
"items": 1
}
}, {
"$match": {
"checkAllElem": true
}
})
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