Is it possible to create a regular expression that can determine if a string contains at least 3 digits, regardless of their order?
(I would appreciate seeing the exact regex solution for this.)
For example:
abk2d5k6 //3 digits
abk25k6d //also has 3 digits
My attempts so far:
.+?(?=\d){3}
Thank you.
(Please provide only regular expressions for learning purposes.)
If you're looking to learn more about this topic, I highly recommend diving into this extensive tutorial.
Alternatively, when it comes to JavaScript regex, the code snippet for ensuring at least three digits could resemble something like:
/^(?:\D*\d){3}/
On the other hand, if your goal is to verify exactly three digits are present, you might use:
/^(?:\D*\d){3}\D*$/
In these expressions, \D represents any non-digit character, * indicates zero or more occurrences of that character, \d signifies any digit character, {3} repeats the subpattern thrice, while ^ and $ respectively denote the start and end of the string.
Another way to achieve the same result is by using the following code:
str.match(/\d/g).length >= 3
This method is straightforward and effectively communicates the purpose without the need for a complex regular expression.
Please note that this solution may not be optimized for speed performance.
After considering your request for "at least" three digits, the solution doesn't have to be overly complex. Here is a simple regex that should suffice:
/\d.*\d.*\d/
This pattern matches a digit followed by zero or more characters, then another digit, and so on. Since I haven't anchored either end, it allows for any number of characters before and after the digits.
console.log(!!"abk2d5k6".match(/\d.*\d.*\d/)); // true
console.log(!!"abk25k6d".match(/\d.*\d.*\d/)); // true
console.log(!!"abkd5k6".match(/\d.*\d.*\d/)); // false (A digit was removed)
console.log(!!"abk2k6d".match(/\d.*\d.*\d/)); // false (A digit was removed)
Alternatively, you can use:
/(\d.*){3}/
console.log(!!"abk2d5k6".match(/(\d.*){3}/)); // true
console.log(!!"abk25k6d".match(/(\d.*){3}/)); // true
console.log(!!"abkd5k6".match(/(\d.*){3}/)); // false (A digit was removed)
console.log(!!"abk2k6d".match(/(\d.*){3}/)); // false (A digit was removed)
As suggested by m.buettner in the comments, instead of using ., you can utilize \D (not a digit):
/\d\D*\d\D*\d/
or
/(\d\D*){3}/
display(!!"abk2d5k6".match(/\d\D*\d\D*\d/)); // true
display(!!"abk25k6d".match(/\d\D*\d\D*\d/)); // true
display(!!"abkd5k6".match(/\d\D*\d\D*\d/)); // false (A digit was removed)
display(!!"abk2k6d".match(/\d\D*\d\D*\d/)); // false (A digit was removed)
display(!!"abk2d5k6".match(/(\d\D*){3}/)); // true
display(!!"abk25k6d".match(/(\d\D*){3}/)); // true
display(!!"abkd5k6".match(/(\d\D*){3}/)); // false (A digit was removed)
display(!!"abk2k6d".match(/(\d\D*){3}/)); // false (A digit was removed)
In summary, there's no need for anchors when seeking an "at least" match.
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