Is there a quicker alternative for handling lengthy inputs?

Question

Is there a quicker alternative for handling lengthy inputs?

Imagine I come across this particular challenge:

And here's how I tackle it:

function bcc(arr) {
    let res = 0;
    for (let i = 0; i < arr.length; i++) {
        if (arr[i] == Math.max(...arr)) {
            res++;
        }
    }
    return res;
}

console.log(bcc([4, 4, 3, 1]));

Initially, my solution works well for an array like [4, 4, 3, 1]. However, when HackerRank presents me with a massive array containing 100,000 elements and expecting an output of 7147, my code fails due to timeout issues. This resulted in me getting only 5 out of 9 problems correct.

Could you offer me a more efficient solution that not only solves this problem quicker but can also be applied to other challenges as well?

javascript arrays

Answer 1

Answer №1

Determine the highest value within the array in advance, rather than with each iteration, and utilize reduce for conciseness:

function findMaxOccurrence(arr) {
  const max = Math.max(...arr);
  return arr.reduce((a, b) => a + (b === max), 0);
}

This decreases the overall computational complexity from O(n ^ 2) to O(n).

Alternatively, you can follow a similar approach as your initial code:

function findMaxOccurrence(array) {
  const max = Math.max(...array);
  let result = 0;
  for (let i = 0; i < array.length; i++) {
    if (array[i] == max) {
      result++;
    }
  }
  return result;
}

Answer 2

Determine the highest value within the array in advance, rather than with each iteration, and utilize reduce for conciseness:

function findMaxOccurrence(arr) {
  const max = Math.max(...arr);
  return arr.reduce((a, b) => a + (b === max), 0);
}

This decreases the overall computational complexity from O(n ^ 2) to O(n).

Alternatively, you can follow a similar approach as your initial code:

function findMaxOccurrence(array) {
  const max = Math.max(...array);
  let result = 0;
  for (let i = 0; i < array.length; i++) {
    if (array[i] == max) {
      result++;
    }
  }
  return result;
}

Answer 3

Answer №2

The flaw in the solution provided is that it has a time complexity of O(n^2), as pointed out by another answer. This inefficiency arises because the maximum value is recalculated during each iteration of the loop instead of being calculated just once. The reason for this is that Math.max needs to traverse the entire array to determine the maximum value, leading to redundant calls within the loop.

While computing the max value at the start is functional, it is not optimal. A more efficient approach would be to calculate it in real-time as the loop progresses. By doing so, the time complexity is reduced from O(2n) to O(n), resulting in improved performance.

function birthdayCakeCandles(ar) {
    var max = 0;
    var candleCount = 0;
    for(var i = 0; i < ar.length; i++) {
        if(ar[i] > max) {
            max = ar[i];
            candleCount = 1;
        } else if (ar[i] === max) {
            candleCount++;
        }
    }
    return candleCount;
}

This revised solution iterates through the array only once, resetting the candle count when encountering a new maximum value and resuming counting thereafter.

Answer 4

The flaw in the solution provided is that it has a time complexity of O(n^2), as pointed out by another answer. This inefficiency arises because the maximum value is recalculated during each iteration of the loop instead of being calculated just once. The reason for this is that Math.max needs to traverse the entire array to determine the maximum value, leading to redundant calls within the loop.

While computing the max value at the start is functional, it is not optimal. A more efficient approach would be to calculate it in real-time as the loop progresses. By doing so, the time complexity is reduced from O(2n) to O(n), resulting in improved performance.

function birthdayCakeCandles(ar) {
    var max = 0;
    var candleCount = 0;
    for(var i = 0; i < ar.length; i++) {
        if(ar[i] > max) {
            max = ar[i];
            candleCount = 1;
        } else if (ar[i] === max) {
            candleCount++;
        }
    }
    return candleCount;
}

This revised solution iterates through the array only once, resetting the candle count when encountering a new maximum value and resuming counting thereafter.

Is there a quicker alternative for handling lengthy inputs?

Answer №1

Answer №2

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