Is there a more efficient method to replace the element at arr[i] without using arr.splice() that is not timing

Having trouble with my solution and suspect that the .splice() function might be in the wrong place since I keep timing out.

The issue:

You have an array of integers. Each move allows you to increase one element by one. Find the minimum number of moves needed to get a strictly increasing sequence from the input.

Example

If inputArray = [1, 1, 1], then arrayChange(inputArray) should equal 3.

My Pseudo code

First, check if the current index is greater than the next index. If not, continue checking through the loop. If yes, add one to the next index and repeat until true. Increment the "moves" variable each time you increase the next index by one. Return the total moves in the end.

function arrayChange(inputArray) { 
   
    for( var i = 0; i < inputArray.length; i++){
        var addition = (inputArray[i+1]+1)
        if(inputArray[i] >= inputArray[i+1]){     
           inputArray.splice(i,0, addition);
        }
    }

    return inputArray;
}

My Error:

Test 1: Execution time limit exceeded. The program took too long to complete execution. Ensure it finishes quickly for all possible inputs.

Answer №1

Reason for Code Failure:

for( var i = 0; i < inputArray.length; i++){//iterate until reaching end of array
    var addition =(inputArray[i+1]+1);
    if(inputArray[i] >= inputArray[i+1]){  //if its not increasing   
       inputArray.splice(i,0, addition);
    }
}

Let's analyze a given input:

arrayChange([1,1]);

In this case, inputArray[i] equals 1, and inputArray[i+1] equals 1. This causes the code to enter the if statement, as 1>=1. Therefore, it adds 1+1 into the array, but not at the end - rather at position 0. Resulting in:

[2,1,1]

The loop continues:

[2,2,2....,1,1]

This cycle is infinite.

To fix this issue, you need to stop at array.length-1 :

for( var i = 0; i < inputArray.length-1; i++){

You must also insert at the correct index and remove one:

inputArray.splice(i+1,1,addition);

Alternative Approach Without Modifying Array:

function numchanges(array){
  var before=array[0],counter=0;
  for(var i=1;i<array.length;i++){
    if(before>=array[i]){
      //we need to change array[i] to before+1, so:
      counter+=(++before)-array[i];
    }else{
     before=array[i];
   }
  }
return counter;
}

console.log(numchanges([1,1,1]));//should return 3

How It Works: A strictly monotonically increasing function would have values like this:

[1,2,3,4,5,10]

One array and its valid counterpart:

[1,1,3,4,5,-1]
[1,2,3,4,5,6]

Calculating the changes needed:

[0,1,0,0,0,7] => 8

The above code keeps track of the valid number (before) and the necessary change while moving from left to right. We start with the first array element:

before=array[0];//1

We then check if we need to make a change starting from i=1. If the current number is valid:

before<array[i]

We proceed:

before=array[i];
i++;//due to the for loop

If the number is invalid, we calculate the correction required:

result+=before+1-array[i];

For example, if before was 5 and now we have -10, we need to adjust it to 6:

result+=6--10//==16

This means we need another 16 corrections...

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