Is it possible to verify whether a function contains a call to another function within it?

Question

Is it possible to verify whether a function contains a call to another function within it?

Consider a scenario in which we have the following nested functions:

function function1(n) {
  function function2() {
    function function3() {
        function function4() {
            return n * 2;
        }
        return function4()
    }
    return function3()
  }
  return function2()
}

Firstly, I am curious if there is a way in JavaScript to determine if a function is being called inside function1 without accessing the actual code. Imagine I only know the name of function1 and it is located in a different JS file.

If the above question is not possible, then how can I check if a specific function (such as function2) is defined within function1 when I know the exact name? Is there a way to verify its presence without analyzing the entire content of function1?

As someone who is new to JavaScript, I appreciate your understanding and patience with my questions. Thank you!

javascript

Answer 1

Answer №1

By calling function1.toString(), you will receive the complete text of the function rather than its execution result. This allows you to explore methods for invoking a function, such as identifying elements before parentheses.

Here is an uncurated demonstration:

function function1(val) {
  function innerFunction1() {
    function innerFunction2() {
        function innerFunction3() {
            return val * 2;
        }
        return innerFunction3()
    }
    return innerFunction2()
  }
  return innerFunction1()
}

const pattern = /.*\(\)/g
const outcome = function1.toString().match(pattern).filter(y => y.search(/function /) < 0)
console.log(outcome)

Answer 2

By calling function1.toString(), you will receive the complete text of the function rather than its execution result. This allows you to explore methods for invoking a function, such as identifying elements before parentheses.

Here is an uncurated demonstration:

function function1(val) {
  function innerFunction1() {
    function innerFunction2() {
        function innerFunction3() {
            return val * 2;
        }
        return innerFunction3()
    }
    return innerFunction2()
  }
  return innerFunction1()
}

const pattern = /.*\(\)/g
const outcome = function1.toString().match(pattern).filter(y => y.search(/function /) < 0)
console.log(outcome)

Answer 3

Answer №2

It's not entirely clear what the intention is for utilizing this feature, so it might lead to an alternative problem.

However, one possible approach could involve utilizing the outdated XY challenge. This would entail utilizing the deprecated Function.caller property to determine which function invoked the currently executing function. Additionally, you could combine this with the widely supported Function.name property to access the name of the calling function.

Answer 4

It's not entirely clear what the intention is for utilizing this feature, so it might lead to an alternative problem.

However, one possible approach could involve utilizing the outdated XY challenge. This would entail utilizing the deprecated Function.caller property to determine which function invoked the currently executing function. Additionally, you could combine this with the widely supported Function.name property to access the name of the calling function.

Is it possible to verify whether a function contains a call to another function within it?

Answer №1

Answer №2

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