Is it possible to utilize gulp to eliminate all require.js define([...]) wrappers throughout the codebase?

Question

Is it possible to utilize gulp to eliminate all require.js define([...]) wrappers throughout the codebase?

Is it possible to test my app without using require.js in order to assess the performance and file size if all files were concatenated into a single one?

I'm contemplating using gulp to gather all *.js files in the app, running a gulp-replace to eliminate the

define([...], function (...) { });

wrapper from the script, and then merging them into a single *.js file.

Could gulp-replace handle this task, and if so, what would be the regex pattern required? Below is an example of a *.js file:

'use strict';

define(['file1', 'file2', 'file3'], function (param1, param2, param3) {
    //...
    //code that should remain after gulp-replace
    //...
});

javascript regex npm gulp

Answer 1

Answer №1

Here is a helpful solution for those looking to achieve the same outcome:

const gulp = require('gulp'),
  concat = require('gulp-concat'),
  replace = require('gulp-replace'),
  uglify = require('gulp-uglify');

gulp.src(['src/**/*.js', '!src/main.conf.js', '!src/**/*_test.js'])
  .pipe(replace(/'use strict';/g, ''))
  .pipe(replace(/define\s?\(\[.*\],\s?function\s?\(.*\)\s?\{/g, ''))
  .pipe(replace(/\}\)\;\s?$/g, ''))
  .pipe(concat('app.js'))
  .pipe(uglify())
  .pipe(gulp.dest('dist'));

This solution assumes you are specifically targeting require.js files. If encountering compile errors, consider using gulp-debug to identify the problematic file.

The assumption here is that the order of file loading is not crucial, which is often the case in AngularJS applications. However, if file order matters, you can specify the desired sequence within the array passed to gulp.src.

Answer 2

Here is a helpful solution for those looking to achieve the same outcome:

const gulp = require('gulp'),
  concat = require('gulp-concat'),
  replace = require('gulp-replace'),
  uglify = require('gulp-uglify');

gulp.src(['src/**/*.js', '!src/main.conf.js', '!src/**/*_test.js'])
  .pipe(replace(/'use strict';/g, ''))
  .pipe(replace(/define\s?\(\[.*\],\s?function\s?\(.*\)\s?\{/g, ''))
  .pipe(replace(/\}\)\;\s?$/g, ''))
  .pipe(concat('app.js'))
  .pipe(uglify())
  .pipe(gulp.dest('dist'));

This solution assumes you are specifically targeting require.js files. If encountering compile errors, consider using gulp-debug to identify the problematic file.

The assumption here is that the order of file loading is not crucial, which is often the case in AngularJS applications. However, if file order matters, you can specify the desired sequence within the array passed to gulp.src.

Is it possible to utilize gulp to eliminate all require.js define([...]) wrappers throughout the codebase?

Answer №1

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