Is it possible to pass additional arguments to `.call()` within this specific scenario?

Here is the code snippet to analyze:

/*jslint white:true, devel:true*/
var foo = function () {
  'strict mode';
  console.log(
    Array.prototype.slice.call(
      /* How can I send more arguments to call after 'arguments'? */
      arguments,
      /*
       This function gets sent to slice.
       If I sent a '2' it would start the array at the third index.
       */
      function () {
        console.log("bar");
      }
    )
  );
};

foo(1, 2, 3, 4, 5, 6);

Exploring the workings of parameters in this scenario. It appears that the second argument is consistently passed to slice.

Is there a way to add another parameter to call here? Or should I reconsider structuring the code to use .slice() and .call() separately?

UPDATE:

Baffled by the negative feedback received on this post. My confusion stemmed from thinking that .slice was dominating instead of receiving all arguments through .call(). Grateful for Quentin's explanation.

Answer №1

It appears that the second parameter is consistently directed to slice.

The initial parameter for call represents the value of this that slice should operate on. Essentially, it mimics arguments.slice(...) if arguments took the form of an array rather than an array-like object lacking its own slice method.

The second parameter for call acts as the first argument for slice. In other words, it signifies the position in the array from which to begin slicing. Passing a function in this manner would not be logical.

Is there a way to supply another parameter to call within this scenario?

Absolutely. Simply proceed to do so.

The third parameter for call denotes the second argument for slice. This determines the index at which slicing should conclude.

As for the fourth parameter of call, it corresponds to the third argument for

slice</code. However, since <code>slice
only accommodates two arguments, providing additional ones would be nonsensical.

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