Is it possible to execute the .push() method on an array a specific number of times without using a for loop?

Question

Is it possible to execute the .push() method on an array a specific number of times without using a for loop?

Currently, I am tackling the "Move Zeroes" Leetcode challenge. The task requires moving all zeroes to the end of the array without altering the sequence of non-zero elements. My strategy involves iterating through the array, splicing out each zero encountered, and keeping count. Subsequently, I plan to append 0 to the array a certain number of times based on the counter. Below is the snippet of my code:

var moveZeroes = function(nums) {
    let counter = 0
    for (let i =0; i<nums.length; i++) {
        if (nums[i]===0) {
            nums.splice(i,1);
            counter+=1;
        }
    }
    nums.push()
};

Moreover, I am aiming to circumvent a secondary loop or introducing the push() method within the initial loop. Instead, I seek alternative methods to execute the push action a set number of times outside the loop structure. I appreciate any insights you may have.

javascript arrays

Answer 1

Answer №1

Absolutely, it is entirely feasible to achieve this by executing the following code:

nums.push(...Array(counter).fill(0))

By exploiting the capability of the push method to handle numerous arguments, the spread syntax effortlessly handles the rest.

Answer 2

Absolutely, it is entirely feasible to achieve this by executing the following code:

nums.push(...Array(counter).fill(0))

By exploiting the capability of the push method to handle numerous arguments, the spread syntax effortlessly handles the rest.

Answer 3

Answer №2

One potential method is to create a workaround by essentially concealing another loop within the process of pushing zeros. This involves generating an array filled with zeros and then pushing the contents of that array. This can be achieved either during:

var moveZeroes = function(nums) {
    let counter = 0
    let zeros = [];        // ***
    for (let i =0; i<nums.length; i++) {
        if (nums[i]===0) {
            nums.splice(i,1);
            counter+=1;
            zeros.push(0); // ***
        }
    }
    nums.push(...zeros)    // ***
};

Alternatively, the same outcome can be reached by adding another loop after the initial action:

var moveZeroes = function(nums) {
    let counter = 0
    for (let i =0; i<nums.length; i++) {
        if (nums[i]===0) {
            nums.splice(i,1);
            counter+=1;
        }
    }
    nums.push(...Array(counter).fill(0)); // ***
};

If you prefer adhering to the splice method, you can integrate the push operation within the existing loop, eliminating the need for a separate step:

var moveZeroes = function(nums) {
    let counter = 0
    for (let i = 0, l = nums.length; i < l; i++) {
    // −−−−−−−−−−−−^^^^^^^^^^^^^^^^    ^^^
        if (nums[i] === 0) {
            nums.splice(i,1);
            nums.push(0);      // ***
            --l                // ***
        }
    }
};

Answer 4

One potential method is to create a workaround by essentially concealing another loop within the process of pushing zeros. This involves generating an array filled with zeros and then pushing the contents of that array. This can be achieved either during:

var moveZeroes = function(nums) {
    let counter = 0
    let zeros = [];        // ***
    for (let i =0; i<nums.length; i++) {
        if (nums[i]===0) {
            nums.splice(i,1);
            counter+=1;
            zeros.push(0); // ***
        }
    }
    nums.push(...zeros)    // ***
};

Alternatively, the same outcome can be reached by adding another loop after the initial action:

var moveZeroes = function(nums) {
    let counter = 0
    for (let i =0; i<nums.length; i++) {
        if (nums[i]===0) {
            nums.splice(i,1);
            counter+=1;
        }
    }
    nums.push(...Array(counter).fill(0)); // ***
};

If you prefer adhering to the splice method, you can integrate the push operation within the existing loop, eliminating the need for a separate step:

var moveZeroes = function(nums) {
    let counter = 0
    for (let i = 0, l = nums.length; i < l; i++) {
    // −−−−−−−−−−−−^^^^^^^^^^^^^^^^    ^^^
        if (nums[i] === 0) {
            nums.splice(i,1);
            nums.push(0);      // ***
            --l                // ***
        }
    }
};

Answer 5

Answer №3

If you're looking for a different method, consider utilizing two loops. In the first loop, move all non-zero elements to the beginning of the array, and in the second loop, fill the remaining elements with zeros.

var array = [0, 1, 2, 0, 0, 0, 3, 0],
    i = 0,
    j = 0;

while (j < array.length) {
    if (array[j] !== 0) array[i++] = array[j];
    j++;
}

while (i < array.length) {
    array[i] = '0';
    i++;
}

console.log(...array);

Answer 6

If you're looking for a different method, consider utilizing two loops. In the first loop, move all non-zero elements to the beginning of the array, and in the second loop, fill the remaining elements with zeros.

var array = [0, 1, 2, 0, 0, 0, 3, 0],
    i = 0,
    j = 0;

while (j < array.length) {
    if (array[j] !== 0) array[i++] = array[j];
    j++;
}

while (i < array.length) {
    array[i] = '0';
    i++;
}

console.log(...array);

Is it possible to execute the .push() method on an array a specific number of times without using a for loop?

Answer №1

Answer №2

Answer №3

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